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Gnesinka [82]
3 years ago
10

Find the area of an equilateral triangle (regular 3-gon) with the given measurement.

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0
Whats the given measurements

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Correct option*<br> PLEASE HELP I WILL GIVE BRAINLIEST
Kryger [21]

Answer:

The answer is A

Step-by-step explanation:

3 0
3 years ago
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If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
Even has a bag of 14 jelly beans. Four of his jelly beans are black, five are red, and five are purple. What is the ratio of the
nirvana33 [79]

Answer: 14:4

Step-by-step explanation:

The amount of jelly beans: 14

The amount of black jelly beans: 4

all beans: black beans

14:4

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Which weighs more, 5 oz or 150 grams?
tatiyna
150 grams because 5 oz is equal to 141 grams
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well from my understanding of the problem and calculations i would say.. (-5.5,0)
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3 years ago
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