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3 years ago

What is 6a²b – 12ab² divided by —2ab? I need help

Mathematics

2 answers:

Hunter-Best [27]3 years ago

8 0

Answer:

Step-by-step explanation:

You can start by rewriting the top equation.

$6a^2b - 12ab^2 = - 2ab (3a + 6b)$

Therefore,

$\frac{6a^2b - 12ab^2}{-2ab} = \frac{-2ab(-3a+6b)}{-2ab} = -3a + 6b$

Lerok [7]3 years ago

8 0

Answer:

$3a^{-1} b^{-1}$ would be my best answer

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1..) 2x +15 = 35

Masja [62]

Answer:

1) $x=10$

2) $x=3$

Step-by-step explanation:

$2x+15=35$

Subtract 15 from both sides

$2x=20$

Divide both sides by 2

$x=10$

$2(10)+15=35$

$20+15=35$

$35=35$

this shows that 10 is the right answer

$7x-3=18$

Add 3 to both sides

$7x=21$

Divide both sides by 7

$x=3$

$7(3)-3=18$

$21-3=18$

$18=18$

this shows that 3 is the right answer

Hope this helps

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3 years ago

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prisoha [69]

Answer:

Step-by-step explanation:

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Bond [772]

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3 years ago

Read 2 more answers

In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96% confidence interval for the mean

Nastasia [14]

Answer:

a) $\bar X =\frac{46+54}{2}=50$

And the margin of error is given by:

$ME= \frac{54-46}{2}= 4$

The confidence level is 0.96 and the significance level is $\alpha=1-0.96=0.04$ and the value of $\alpha/2 =0.02$ and the margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

We can calculate the critical value and we got:

$z_{\alpha/2} = 2.05$

And if we solve for the deviation like this:

$\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}$

And replacing we got:

$\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45$

b) $ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828$

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor $\sqrt{2}$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma$ represent the population standard deviation

n=80 represent the sample size

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case we can calculate the mean like this:

$\bar X =\frac{46+54}{2}=50$

And the margin of error is given by:

$ME= \frac{54-46}{2}= 4$

The confidence level is 0.96 and the significance level is $\alpha=1-0.96=0.04$ and the value of $\alpha/2 =0.02$ and the margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

We can calculate the critical value and we got:

$z_{\alpha/2} = 2.05$

And if we solve for the deviation like this:

$\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}$

And replacing we got:

$\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45$

Part b

For this case is the sample size is doubled the margin of error would be:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828$

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor $\sqrt{2}$

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3 years ago

Imagine that you must cross the hallway staying an equal distance from each laser. Il you get closer to one laser than the other

Karo-lina-s [1.5K]

Answer:

can you answer this first

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