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Klio2033 [76]
4 years ago
14

Suppose that the final exam scores of all statistics students at a nearby college are collected and are found to have mean 82.6,

with a standard deviation of 7.5 percentage points. Interpret the value of the standard deviation.
Mathematics
1 answer:
ale4655 [162]4 years ago
6 0

the data points are 7.5 points away from the mean 82.6

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How do your write a feaction with a denominator of 20 as a decimal?​
Maslowich

Answer:

Step-by-step explanation:

What is 20 as a decimal? To write 20 as a decimal you have to divide numerator by the denominator of the fraction. 20 is not a fraction so it is a decimal already. And finally we have: 20 as a decimal equals 20

7 0
3 years ago
Identify the zeros of the function f(x) = 2x^2 − 4x + 5 using the Quadratic Formula
Nostrana [21]

For this case we have that by definition, the roots, or also called zeros, of the quadratic function are those values of x for which the expression is 0.

Then, we must find the roots of:

2x ^ 2-4x + 5 = 0

Where:

a = 2\\b = -4\\c = 5

We have to:x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Substituting we have:

x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (2) (5)}} {2 (2)}\\x = \frac {4 \pm \sqrt {16-40}} {4}\\x = \frac {4 \pm \sqrt {-24}} {4}

By definition we have to:

i ^ 2 = -1

So:

x = \frac {4 \pm \sqrt {24i ^ 2}} {4}\\x = \frac {4 \pm i \sqrt {24}} {4}\\x = \frac {4 \pm i \sqrt {2 ^ 2 * 6}} {4}\\x = \frac {4 \pm 2i \sqrt {6}} {4}\\x = \frac {2 \pm i \sqrt {6}} {2}

Thus, we have two roots:

x_ {1} = \frac {2 + i \sqrt {6}} {2}\\x_ {2} = \frac {2-i \sqrt {6}} {2}

Answer:

x_ {1} = \frac {2 + i \sqrt {6}} {2}\\x_ {2} = \frac {2-i \sqrt {6}} {2}

3 0
4 years ago
If f(x) is a function and f(1) = 5, then which of the following could not be true?
Natasha_Volkova [10]
It can't be f(1) = 1 because a function can't have two images on the same x.
8 0
3 years ago
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h(n)=-13nh(n)=−13nh, left parenthesis, n, right parenthesis, equals, minus, 13, n Complete the recursive formula of h(n)h(n)h, l
mr Goodwill [35]

Answer:

h(1)=-13

h(n)=h(n-1)-13, n\geq 2

Step-by-step explanation:

We are given that

h(n)=-13n

We have to find the recursive formula of h(n).

Substitute n=1

h(1)=-13

n=2

h(2)=-13-13=-26=h(1)-13

n=3

h(3)=-13(3)=-39=-26-13=h(2)-13

h(4)=-13(4)=-52=-39-13=h(3)-13

:

:

:

h(n)=h(n-1)-13

Therefore, the recursive formula is given by

h(1)=-13

h(n)=h(n-1)-13, n\geq 2

5 0
4 years ago
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nlexa [21]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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