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dusya [7]
2 years ago
10

Successfulness of the Competition policy in South Africa- support and graphs​

Mathematics
1 answer:
jenyasd209 [6]2 years ago
6 0

Answer:

Answer to the following question is a follows;

Step-by-step explanation:

The following are a few examples of how South Africa's competitiveness policy has been successful:

⇒ Consumers or buyers were given a variety of product options as well as competitive prices.

⇒ In 1984, practises like horizontal cooperation and resale price maintenance and control were ruled illegal.

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Jerry's Seed Palace claims that 80% of its lima bean seeds will germinate. Suppose the company's claim is true. Callie buys a pa
Mekhanik [1.2K]

Answer:

A

Step-by-step explanation:

This is a Bernoulli trial problem.

Since the probability that the seed will germinate is 80% or 0.8, the probability that they won’t germinate is 0.2

Now let’s say the probability to germinate is p and the probability not to is a, we can now set up the Bernoulli equation in this regard. Since we are proposing that exactly 14 will germinate, it means 6 are not expected to germinate

P(14) = 20C14 (0.8)^14 (0.2)^6 = 0.109099700973

Option A is the right answer

3 0
2 years ago
Which measurement is equivalent to 110 mL
ale4655 [162]
Your answer is 0.110 L

110mL=0.110L
4 0
3 years ago
What are the coordinates of the fourth point that could be connected with (–8, 0), (1, 0), and (1, –5) to form a rectangle?
Ksju [112]
(-8,-5). If you think about it, for a rectangle, the x-coordinates must be the same in two pairs and the y-coordinates must be the same in two pairs. Since there are already 2 0's, 2 1's, you need a -8 and -5 to complete it. Hence, the last coordinate is (-8,-5)
5 0
3 years ago
Ayúdenme en este ejercicio por favor
lapo4ka [179]

Para poder encontrar el número total de conjuntos de diferentes números, lo primero que debemos contar es el número de opciones para cada una de las selecciones.

A) Para el primer número tenemos 47 opciones

para el segundo número tenemos 46 opciones, pues una ya fue seleccionada.

Para el tercer número tenemos 45 opciones

Para el cuarto número tenemos 44 opciones

Para el quinto número tenemos 43 opciones

Para el sexto número, el mega número, tenemos 27 opciones.

El número total de combinaciones es igual al producto entre los numeros de opciones:

C = 47×46×45×44×43×27 = 4,969,962,360

B) Ahora sabemos que dos de los primeros 5 números tienen valores fijos A y B.

Asumamos que son el primero y segundo número.

Entonces:

El primer número es A (1 opcion)

El segundo número es B (1 opcion)

El tercer número tiene 45 opciones (por que dos ya fueron seleccionadas)

El cuarto número tiene 44 opciones

El quinto número tiene 43 opciones

El sexto número tiene 27 opciones.

Para encontrar el número total de combinaciones no solamente deberemos multiplicar los números de opciones, tambien tendremos que tener en cuenta el número de permutaciones de 2 elementos (A y B) entre los primeros 5 posibles espacios.

Para calcular esto vemos cuantas posibles opciones tiene cada uno de ellos.

El número A tiene 5 posibles posiciones (5 opciones)

El número B tiene 4 posibles posiciones (pues una esta ocupada por A)

asú, el número de permutaciones es:

P = 5*4 = 20

Asi, en este caso el número total de combinaciones es:

C = (1×1×45×44×43×27)×20 = 45,975,600

Si quieres aprender más, puedes leer:

brainly.com/question/21591279

7 0
2 years ago
A rectangle has a perimeter of 30 and a length of 10. Find the width.
bonufazy [111]

Answer:

5

Step-by-step explanation:

8 0
2 years ago
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