Answer:
30,240 ways
Step-by-step explanation:
This question is bothered on permutation. Permutation has to do with arrangement.
If there are 10 computers and 5 students, the number of ways students will sit at the computers if no computer has more than one student can be expressed as;
10P5 = 10!/(10-5)!
10P5 = 10!/(5)!
10P5 = 10*9*8*7*6*5!/5!
10P5 = 10*9*8*7*6
10P5 = 30,240
Hence the number of ways is 30,240 ways
I reduced the equation to a - 6 (2/3)
Answer: it would be B or C
Step-by-step explanation: Hope this helps :)
1
is the answer you're looking for.
Answer choice B is the correct answer the rest don't make sense.
