Question

Please solve this question. ​

Answer 1

Answer :

Ram started his journey at 6:00 AM with an average speed at 20km/hr.

Hari started his journey two hours later (at 8:00 AM) with an average speed of 30km/hr.

We have to find time at which they meet each other$.$

★ Let they meet each other after t hours wrt 6:00 AM.

At that time, distance covered by ram must be equal to the distance covered by hari.

We know that,

• distance = speed × time

➤ Distance covered by Ram :

⭆ d₁ = v₁ × t

⭆ d₁ = 20 × t

➤ Distance covered by Hari :

Since hari started his journey after 2 hours so will take time = (t - 2) hours

⭆ d₂ = v₂ × (t - 2)

⭆ d₂ = 30 × (t - 2)

⭆ d₂ = 30t - 60

Now,

➠ d₁ = d₂

➠ 20t = 30t - 60

➠ 30t - 20t = 60

➠ 10t = 60

➠ t = 6 hrs

∴ They will meet at (6 + t) = 12PM

Hope It Helps!

Answer 2

Answer:  12:00 pm  (Noon)

Step-by-step explanation:

Let t represent the time (in hours) from 6:00 am

Use distance (d) = rate (r) × time (t)

Ram: time = t,      r = 20     →      d = 20t

Hari: time = t - 2, r = 30    →       d = 30(t - 2)

Use Substitution method to solve the system of equations:

20t = 30(t - 2)

20t = 30t - 60

-10t = -60

    t = 6

They travel the same distance when Ram rides his bike for 6 hours

and Hari rides his bike for 4 hours.

Ram: 6:00 am + 6 hours = 12:00 pm (Noon)

Hari: 8:00 am + 4 hours = 12:00 pm (Noon)    $\checkmark$