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DIA [1.3K]
3 years ago
5

Jay graphed the line y = x-6 on a coordinate plane. He drew an image of the line 3 units to the right of the original line. What

is the same about the two lines?
Mathematics
2 answers:
lesantik [10]3 years ago
8 0

Answer:

No, he is not correct. Jay drew a line through the origin, but the line did not connect all three points. Not all the points lie on the line, which is necessary for a proportional relationship.

Step-by-step explanation:

It's the sample response.

Solnce55 [7]3 years ago
6 0
The lines are parallel, because they have the same gradient but are just in different positions ie. y = x-9.
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There are 13 female board members and 10 male board members. If a committee of 10 members is randomly chosen, what is the probab
Mama L [17]

Answer:

0.131

Step-by-step explanation:

(13C4×10C6)/26C10

= 975/7429

= 0.131 (3 sf)

4 0
3 years ago
Solve the equation using square roots. X^2+16=0
alexgriva [62]

Answer:

<u>The answer is :</u>

<u>x₁ = 4</u>

<u>x₂ = -4</u>

Step-by-step explanation:

Let's solve the equation using square roots.

X^2+16=0

x² + 16 = 0

x² = -16 (Adding 16 at both sides of the equation)

√x² = i√16 (Square root to both sides of the equation)

x = +/- 4i (Roots of the solution)

<u>x₁ = 4i</u>

<u>x₂ = -4i</u>

5 0
3 years ago
Read 2 more answers
What is the measure of Z PRQ?<br> 62°<br> 108°<br> P.<br> N<br> R
Ksju [112]
The measure of PRQ is 46 degrees.
6 0
2 years ago
The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
What is the square root of 5?
shutvik [7]
5 x 5 = 25

answer: 25.
7 0
3 years ago
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