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pashok25 [27]
3 years ago
9

A 5601 turn, 9.1 cm long solenoid carries a current of 18.2 Amperes. What is the magnetic field inside this solenoid?

Physics
1 answer:
Anastasy [175]3 years ago
8 0

Answer:

Magnetic field = 1.41 T

Explanation:

Magnetic field of solenoid, B = μnI

μ = 4π x 10⁻⁷N/A²

Number of turns per meter, n=\frac{N}{L}=\frac{5601}{9.1\times 10^{-2}}=6.15\times 10^4turns/m

Current, i = 18.2 A

B = μnI = 4π x 10⁻⁷ x 6.15 x 10⁴ x 18.2 = 1.41 T

Magnetic field = 1.41 T

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Ruff, the 50 cm tall Labrador Retriever stands 3 m from a plane mirror and looks at his image. What is Ruff’s image position and
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If humans cannot see ultraviolet waves, how can ultravoilet light be used to gather evidence of a crime?
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4 0
3 years ago
A person makes ice tea by adding ice to 1.8 kg of hot tea, initially at 80°C. How many kilograms of ice, initially at 0.00°C, ar
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The required mass of ice is 12.5 kg.

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Final temperature of mixture = 10°C = 283 K

Heat of fusion of ice, L = 334 kJ/kg

Specific heat capacity of tea, c_{t} = Specific heat capacity of water = 4190 J/kg/K

Heat lost tea = Heat gained by ice

m_{t}c_{t}ΔT_{t} = m_{i}L +  m_{i}c_{i}ΔT_{t}

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1.8 x 4190 x (353 - 283) = m_{i}(334 + (4190 x (283 - 2730))

1.8 x 4190 x 70 = m_{i}(334 + (4190 x 10))

527940 = 42234m_{i}

m_{i} = \frac{527940}{42234}

    = 12.5004

m_{i} = 12.5 kg

The required mass of ice is 12.5 kg.

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