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____ [38]
3 years ago
6

What is necessary to apply force

Physics
2 answers:
tensa zangetsu [6.8K]3 years ago
5 0
Energy is necessary to apply force
IRINA_888 [86]3 years ago
4 0
To push pull or lift something
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a 3.18-kg rock is released from rest at a height of 26.6 m. ignore air resistance and determine (a) the kinetic energy at 26.6 m
antiseptic1488 [7]

Answer:

(a) 0 J

(b) 828.96 J

(c) 828.96 J

(d) 828.96 J

(e) 0 J

(f) 828.96 J

Explanation:

Given:

Mass of the rock is, m=3.18\ kg

Initial height of the rock is, h_{i}=26.6\ m

Final height of the rock is, h_f=0\ m

Initial velocity of the rock is, v_i=0\ m/s(Rest)

Acceleration due to gravity is, g=9.8\ m/s^2

(a)

Initial kinetic energy is given as:

K_i=\frac{1}{2}mv_i^2

Plug in the given values and solve for 'K_i'. This gives,

K_i=\frac{1}{2}\times 3.18\times 0^2=0

Therefore, initial kinetic energy is 0 J.

(b)

Initial potential energy is given as:

U_i=mgh_i\\U_i=3.18\times 9.8\times 26.6=828.96\ J

Therefore, initial potential energy is 828.96 J.

(c)

Mechanical energy is equal to the sum of kinetic and potential energy. It is always a constant value. Therefore,

ME=K_i+P_i\\ME=0+828.96=828.96\ J

Therefore, mechanical energy at 26.6 m is 828.96 J.

(d)

Now, at the final height of 0 m, the decrease in potential energy will be equal to the increase in the kinetic energy. In other words, the potential energy at the start will be converted to kinetic energy at the bottom.

Therefore, kinetic energy at the 0 m is given as:

K_f=U_i=828.96\ J

(e)

Potential energy at the final height is given as:

P_f=mgh_f=3.18\times 9.8\times 0=0\ J

Therefore, final potential energy is 0 J.

(f)

Total mechanical energy is a constant and doesn't depend on the height.

So, total mechanical energy at 0 m is same as that at 26.6 m.

Total mechanical energy is 828.96 J.

8 0
4 years ago
What is an example of a secondary group?
Angelina_Jolie [31]

Answer:(D)The teachers from the science department

Explanation:I took the quiz

3 0
3 years ago
A cyclotron designed to accelerate protons has a magnetic field of magnitude 0.15 T over a region of radius 7.4 m. The charge on
klio [65]

Explanation:

It is given that,

Magnetic field, B = 0.15 T

Charge on a proton, q=1.60218\times 10^{-19}\ C

Mass of a proton, m=1.67262 \times 10^{-27}\ kg

The cyclotron frequency is given by :

f=\dfrac{qB}{2\pi m}

f=\dfrac{1.60218\times 10^{-19}\ C\times 0.15\ T}{2\pi \times 1.67262 \times 10^{-27}\ kg}

f = 2286785.40 Hz

or

\omega=14368296.44\ rad/s

\omega=1.43\times 10^7 rad/s

Hence, this is the required solution.

8 0
3 years ago
a graph compares the weight and height of several different breeds of cat. What type of model is the graph?
pickupchik [31]

Answer: Mathematical Model

Explanation:

Took the test

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A piano has a mass of 99 kg. What is the weight of the piano?
Blababa [14]

Explanation:

weight of the piano = mg

w = 99 x 10 =990 N

7 0
3 years ago
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