Okay so we have this question of the week thing and this week our answer is 4 so i need a algebra problem that is a two step equ
2 answers:
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Answer:
The farmer have at first <u>202</u> chickens.
Step-by-step explanation:
Given:
A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as ducks left.
Now, to find the chickens farmer have at first.
Let the chickens be
And, the ducks be
<em>As, the farmer had twice as many chickens as ducks on his farm.</em>
So, ......(1)
<em>As, given the farmer after selling 166 chickens and ducks, he had half as many chickens as ducks left.</em>
According to question:
Substituting the value of from equation (1) we get:
<em>By cross multiplying we get:</em>
<em>Adding both sides 332 we get:</em>
<em>Subtracting both sides by </em><em> we get:</em>
<em>Dividing both sides by 3 we get:</em>
Now, to get the number of chickens substituting the value of in equation (1):
Therefore, the farmer have at first 202 chickens.