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iren2701 [21]
3 years ago
15

What is measurement?

Mathematics
1 answer:
Liula [17]3 years ago
3 0
the action of measuring something
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There are 2 cats on each house roof, and there are 15 cats on the ground. The table shows how the number of cats, c, depends on
Nuetrik [128]

Answer: c = 2h + 15

Step-by-step explanation: Each house (h) adds 2 cats. We represent that with 2h. Then we add the constant 15 on the ground as +15.

4 0
3 years ago
a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
3 years ago
Find the value of 2 devide3times16​
Nikolay [14]

Answer:

32/3

Step-by-step explanation:

6 0
2 years ago
Simplify (5n^4)^-3. Assume n = 0.
denpristay [2]

Answer:

0

Step-by-step explanation:

5*0=0

0^4=0

0^-3=0

8 0
2 years ago
Read 2 more answers
A²- b² =<br> a² + b² =<br> (a + b)³ =
trasher [3.6K]

Answer:

a²- b²=(a+b)(a-b)

a² + b²=(a+b)²-2ab or (a-b)²+2ab

(a + b)³=a³+3a²b+3ab²+b³ or, a³+b³+3ab(a+b)

5 0
3 years ago
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