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3 years ago

The graph shown below is a scatter plot:

Mathematics

2 answers:

JulijaS [17]3 years ago

7 0

C.) Point L is an Outlier.

[ It is because, each & every point shows same pattern but L is exception to the rule & stays out of the average values ]

Hope this helps!

Sphinxa [80]3 years ago

6 0

<h2>Answer:</h2>

The point on the scatter plot that is an outlier is:

Point L.

<h2>Step-by-step explanation:</h2>

We know that an outlier is a data point that stands out of the rest of the data points in the given data set.

Clearly after looking at the scatter plot we observe that the data point L is isolated from the rest of the data points that is it is not closely related to other points of the set.

Hence, the outlier is:

Point L.

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Which is more 1 kilometer or 551 meters?

lora16 [44]

Answer:

1 kilometer is more

Step-by-step explanation:

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3 years ago

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The function h(t) = 300 – 16t represents the height of a ball (in feet) dropped from 300 feet after t seconds. What will be the

Vaselesa [24]

We are given the function expressed as:

<span>h(t) = 300 – 16t

where h is the height of the ball in time t.

We calculate the height at time equal to 2.4 seconds as follows:

</span>h(t) = 300 – 16(2.4)
h(t) = 261.6 ft

Hope this answers the question. Have a nice day.

4 0

4 years ago

From a window 20 feet above the ground, the angle of elevation to the top of a building across

Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation: Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

$\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},$

and from the right-angled triangle WAB, we have'

$\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.$

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0

3 years ago

Please help no troll im really confused i'm offering 20 points

MatroZZZ [7]

Answer:

4) choice 1) 14.7 cm

5) choice 2) 14.8 cm

Step-by-step explanation:

4) 10^2 + 10^2 + 4^2 = 216

sq rt 216 = 14.7

5) 14^2 + 3^2 + 4^2 = 221

sq rt 221 = 14.86

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3 years ago

Sally graphs a system of inequalities as shown below:

sdas [7]

Step-by-step explanation:

first inequality :

x + 2y ≥ 10

second inequality :

x - y ≤ -2

6 0

3 years ago