Rudy is training for a race. On Monday he ran 2

1 answer:

7 0

Distance ran by Rudy on Monday = 2 km
Percentage of increase in distance of running each day = 15%
Let us assume that the day on which Rudy will run 4 km = x
Then
2 + 0.15x = 4
0.15x = 2
x = 2/0.15
= 13.3
From the above deduction we can conclude that Rudy will run more than 4 km on the 14th day or on Sunday. I hope the procedure is clear enough for you to understand.

You might be interested in

Put the following equation of a line into slope-intercept form, simplifying all

inessss [21]

In slope intercept form its, y=2x-2

8 0

2 years ago

Full explanation please<br> Will mark brainlist :)

Afina-wow [57]

Answer:B

Step-by-step explanation:

3 0

2 years ago

In a city, the distance between the library and the police station is 3 miles less than twice the distance between the police st

deff fn [24]

The distance between the police station and the fire station is x.
The distance between the library and the police station is 3 miles less than twice the distance between the police station and the fire station, so it is 2x-3. This distance is equal to 5 miles.

$2x-3=5 \\
2x=5+3 \\
2x=8 \\
x=\frac{8}{2} \\
x=4$

The police station and the fire station are 4 miles aparat.

5 0

3 years ago

Read 2 more answers

Which of these is an equivalent expression for X ^-3 that uses positive exponents

qaws [65]

X^-3 = 1/(x³)

............,.......

5 0

3 years ago

There are eight wires which need to be attached to a circuit board. A robotic device will attach the wires. The wires can be att

Illusion [34]

Answer: 40320 sequence to test.

Step-by-step explanation:

we have given the following data:

No of wires which need to be attached to a circuit board = 8

What We need to find is the number of possible sequences of assembly that must be tested.

Using our multiplication rule of counting we arrive at,

Number of possible sequences of assembly is given by

8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1

= 40320

i.e. there are 8 choices for the first wire, 7 choices for the second wire, 6 choices for the third wire, 5 choice for the fourth wire same till the 8th wire.

Hence, there are 40320 possible sequences of assembly.

3 0

3 years ago