Answer:
Step-by-step explanation:
bc²-2a/b=6(3)²-2×12/6=54-4=50
Answer:
I’m guessing you subtract the numbers from the inside of the parenthesis and then multiply the two.
(-5)(-11) = 55
I hope this is correct.
Because 14 tens is 10+4 tens
10 tens is a hundred
so 14 tens is a hundred + 4 tens
The remainder is 5. To calculate this, first, divide 599 by 9 to get the largest multiple of 9 before 599. 5/9 < 1, so carry the 5 to the tens, 59/9 = 6 r 5, so carry the 5 to the digits. 59/9 = 6 r 5 again, so the largest multiple is 66. Multiply 66 by 9 to get 594, and subtract this from 599 to get 5, the remainder.