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2 years ago

I need halp psl bfghjhg

Mathematics

2 answers:

fredd [130]2 years ago

7 0

Answer:

Step-by-step explanation: 4.6 grams?

Rzqust [24]2 years ago

5 0

Answer:

<h3>4.6 grams to</h3>

Step-by-step explanation:

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Answer it and I'll give brainliest and 5 stars

sergiy2304 [10]

Answer:

1 over x 2

Step-by-step explanation:

kdbxciu ejgkvbsdv evdjhcxv

7 0

3 years ago

3. Suppose your bank honors a check for which you don't have sufficient funds in your checking account. This action means that y

ololo11 [35]

<span>If you had a check that you don't have sufficent funds for that has been run through the bank the bank will usually charge you an overdraft fee. This means that you have arranged an overdraft loan/agreement with the bank. The bank will go ahead and pay the fund to the person or company you wrote the check to. You will have a certain amount of time to put the money back into your account and pay the overdraft fee. Many banks will give you 24 hours to cover the check before they charge you a fee. The fee is usually around $25 dollars, but could be more depending on your bank rules. </span>

6 0

3 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

2 years ago

Ank estimated that he drove about 450 miles in a week. He actually drove 485 miles. Find the percent error in Hank's estimate. R

yanalaym [24]

Answer:

7.2%

Step-by-step explanation:

Given data

Estimate=450miles

Actual= 485 miles

%error= actual-estimate/ actual*100

%error=35/ 485*100

%error=0.072*100

%error=7.2%

5 0

2 years ago

What are 5 numbers that have 5, 11, and 2 as prime factors

Firdavs [7]

110, 220, 330, 440, 550

hope this helps

5 0

3 years ago