Answer:
It will take <u><em>80 days</em></u> for the bull calf to reach a weight of 500 kilograms.
Step-by-step explanation:
Given:
The weight of a bull calf is 388 kilograms.
Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.
Required weight which to be increased = 500 - 388 = 112 kilograms.
Rate of weight increase = ![1\frac{2}{5}=\frac{7}{5}](https://tex.z-dn.net/?f=1%5Cfrac%7B2%7D%7B5%7D%3D%5Cfrac%7B7%7D%7B5%7D)
=
Thus, the time required = ![\frac{required\ weight}{rate\ of\ weight}](https://tex.z-dn.net/?f=%5Cfrac%7Brequired%5C%20weight%7D%7Brate%5C%20of%5C%20weight%7D)
=
=
<em>The time required = 80 days</em>.
Therefore, it will take 80 days for the bull calf to reach a weight of 500 kilograms.
29 times 35 would be 1,015
Answer:
.
Step-by-step explanation:
If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is
.
Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)
Hence, β = - 3 and α + a = 1 and α - a = -3
Now, solving those two equations of α and a we get,
2α = - 2, ⇒ α = -1 and
a = 1 - α = 2.
Now, eccentricity of the hyperbola is given by
{Since
given}
Therefore, the equation of the given hyperbola will be
. (Answer)
I’m not sure. But I’m sure someone will help you. I haven’t done it in a while. Sorry about that
Answer:
80 hours
Step-by-step explanation:
let d represent doug, let l represent laura
first, set up a system of equations representing the problem:
since doug spent 10 less than twice the hours laura did, and we know that the total amount of hours they spent together is 230:
l=2d+10
d+l=230
then solve:
*first i rearranged the equations so i can solve this system of equations using elimination method*
l-2d=10
l+d=230
*subtract*
3d=240
d=80
so, doug spent 80 hours in the lab