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Answer:
m∠EGF = 65° and m∠CGF = 115°
Step-by-step explanation:
Given;
∠EFG = 50°
EF = FG
Solution,
In ΔEFG m∠EFG = 50° and EF = FG.
Since triangle is an isosceles triangle hence their base angles are always equal.
∴
Let the measure of ∠EGF be x.
∴
Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."
m∠EFG + m∠FEG + ∠EGF = 180
Hence
m∠EGF = 65°
Also 'The sum of angles that are formed on a straight line is equal to 180°."
m∠EGF + m∠CGF = 180°
65° + m∠CGF = 180°
m∠CGF = 180° - 65° = 115°
Hence m∠EGF = 65° m∠CGF = 115°
Answer:
x || t, [Given]
[Given] ......[1]
Transversal defined as a line that cuts across two or more Parallel lines.
When two parallel lines are cut by a transversal, then the pairs of corresponding angles are equal in measure.
[Corresponding Angle theorem] ......[2]
Substitute value [1] in [2] we have;
[Substitution Property]
When two lines are cut by a transversal and the alternate exterior angles are equal in measure, then the lines are parallel.
k || w [ By Alternative Exterior Angle Theorem] Hence proved!
