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Helen [10]
3 years ago
9

What’s the answer i need help

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0
I believe the answer is

B
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Step-by-step explanation:

there are more two-legged pirates than one-legged pirates

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Somebody please help me with this geometry work
dimulka [17.4K]

Answer:

m∠EGF = 65°  and m∠CGF = 115°

Step-by-step explanation:

Given;

∠EFG = 50°

EF = FG

Solution,

In ΔEFG m∠EFG = 50° and EF = FG.

Since triangle is an isosceles triangle hence their base angles are always equal.

∴m\angle FEG = m\angle EGF

Let the measure of ∠EGF  be x.

∴ m\angle FEG = m\angle EGF = x

Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."

m∠EFG + m∠FEG + ∠EGF = 180

50\°+x+x=180\°\\50\°+2x=180\°\\2x= 180\°-50\°\\2x=130\°\\x=\frac{130}{2}= 65\°

Hence

m∠EGF = 65°  

Also 'The sum of angles that are formed on a straight line is equal to 180°."

m∠EGF + m∠CGF = 180°

65° + m∠CGF = 180°

m∠CGF = 180° - 65° = 115°

Hence m∠EGF = 65°  m∠CGF = 115°

8 0
3 years ago
Math help please!
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Answer:

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m\angle 16 = m\angle 7     [Given]                      ......[1]

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When two parallel lines are cut by a transversal, then the pairs of corresponding angles are equal in measure.

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Substitute value [1] in [2] we have;

m\angle 7 =m\angle 1   [Substitution Property]

When two lines are cut by a transversal and the alternate exterior angles are equal in measure, then the lines are parallel.

k || w                     [ By Alternative Exterior Angle Theorem]       Hence proved!

3 0
3 years ago
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