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kow [346]
4 years ago
10

What multiplies to 45 and adds to 10

Mathematics
1 answer:
adelina 88 [10]4 years ago
6 0
I dont think anything does.

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A metal pipe measuring 3.5m weighs 12.67kg. How much does 1m of this <br> pipe weigh?
allochka39001 [22]

Answer:

3.62kg

Step-by-step explanation:

3.5m=12.67kg

1m=?

=1m/3.5m×12.67kg

=3.62kg

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2 years ago
Numbers are measurements of a right triangle 8,7,5<br> true or false
aleksandr82 [10.1K]
The correct answer is FALSE.
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4 years ago
The number of times per minute that a hummingbird's wings flap is normally distributed with a mean of 145 and a standard deviati
klemol [59]

Answer:

a) 0.0013

b) 0.9544

c) 84.13 percentile.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 145

Standard Deviation, σ = 2

We are given that the distribution of wings flap is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( flaps its wings more than 151 times a minute)

P( x > 151) = P( z > \displaystyle\frac{151 - 145}{2}) = P(z > 3)

= 1 - P(z \leq 3)

Calculation the value from standard normal z table, we have,  

P(x > 151) = 1 - 0.9987 = 0.0013

b) P( flap their wings between 141 and 149 times per minute)

P(141 \leq x \leq 149)\\\\ = P(\displaystyle\frac{141 - 145}{2} \leq z \leq \displaystyle\frac{149-145}{2})\\\\ = P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.9772 - 0.0228 = 0.9544

c) Percentile of  hummingbird that flaps its wings 147 times a minute

P( x < 147) = P( z < \displaystyle\frac{147 - 145}{2}) = P(z < 1)

Calculation the value from standard normal z table, we have,  

P(x < 147) = 0.8413

Thus, A hummingbird that flaps its wings 147 times a minute is in the 84.13 percentile.

3 0
3 years ago
.5555555556 as a fraction?
kifflom [539]
1388888889/2500000000
4 0
3 years ago
Read 2 more answers
Find the magnitude and direction of 1/2r
stich3 [128]

Answer:

C

Step-by-step explanation:

0.9 meters. 170 degrees

4 0
3 years ago
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