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marta [7]
3 years ago
10

What is the answer? I need it now ​

Mathematics
1 answer:
Musya8 [376]3 years ago
3 0

The answer is a:

It's the only one that cannot be simplified. A number that will divide evenly into both the numerator and denominator so it can be reduced, or The numerator must be greater than the denominator, (an improper fraction), so it can be converted to a mixed number.

(I was a teensy bit confused from last time's answer, because it said select the CHOICES below sooo...)

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What relationship between the circumference and the diameter is suggested by your observation?
TiliK225 [7]

Answer:

  The ratio of circumference to diameter is a constant

Step-by-step explanation:

The first line on the page tells you the relation: the ratio of the circumference to the diameter is about 3.14.

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Another way to say this is that the circumference is about 3.14 times the diameter.

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3 years ago
How to write 11001195 in words​
avanturin [10]

Answer:

Eleven million one thousand one hundred ninety-five

6 0
3 years ago
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Please help! Will give brainliest (10 points)
Zinaida [17]

Answer:

Tn=a+(n-1)d

a=a1

Tn=a1+(n+1)d

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2 years ago
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Calculate the side lengths a and b to two decimal places.
Zinaida [17]

Answer:

a=10.92 units

b=14.51 units

Step-by-step explanation:

We are given that c=6 units

\angle A=43^{\circ}

\angle B=115^{\circ}

We have to find the side length a and b.

We know that sum of angles of a triangle =180 degrees

\angle A+\angle B+\angle C=180

Substitute the values then we get

43+115+\angle C=180

158+\angle C=180

\angle C=180-158=22^{\circ}

sine law: \frac{a}{sin A}=\frac{b}{sin B}=\frac{c}{sin C}

\frac{a}{sin 43^{\circ}}=\frac{6}{sin 22^{\circ}}

a=\frac{6}{sin 22^{\circ}}\times sin 43^{\circ}

a=10.92 units

\frac{b}{sin 115^{\circ}}=\frac{6}{sin 22^{\circ}}

b=\frac{6}{sin 22^{\circ}}\times sin 115^{\circ}=14.51

b=14.51 units

6 0
3 years ago
Can someone help on both of the questions, i dont get it
o-na [289]

Answer:

A. finished 1km

Step-by-step explanation:

b. 8km per hour

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3 years ago
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