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zaharov [31]
3 years ago
14

Help with this question!!!

Mathematics
2 answers:
olga55 [171]3 years ago
8 0
D is the only answer................
trapecia [35]3 years ago
4 0
The answer is D
THANK ME
You might be interested in
Find two numbers whose difference is 196 and whose product is a minimum.
ch4aika [34]
98, -98. how ya gonna make that twenty characters long
7 0
4 years ago
-
alisha [4.7K]

Answer:

d=3\sqrt{2}\ units

Step-by-step explanation:

<u><em>The complete question is</em></u>

Line L contains points (3, 5) and (7, 9). Points P has coordinates (2, 10). Find the distance from P to L

step 1

Find the equation of the line L contains points (3,5) and (7,9)

<em>Find the slope</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the given values

m=\frac{9-5}{7-3}

m=\frac{4}{4}=1

<em>Find the equation of the line in point slope form</em>

y-y1=m(x-x1)

we have

m=1\\point\ (3,5)

substitute

y-5=(1)(x-3)

isolate the variable y

y=x-3+5

y=x+2 -----> equation A

step 2

Find the equation of the perpendicular line to the given line L  that passes through the point P

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal

so

The slope of the given line L  is m=1

The slope of the line perpendicular to the given line L  is

m=-1

<em>Find the equation of the line in point slope form</em>

y-y1=m(x-x1)

we have

m=-1\\point\ (2,10)

substitute

y-10=-(x-2)

isolate the variable y

y=-x+2+10

y=-x+12 ----> equation B

step 3

Find the intersection point equation A and equation B

y=x+2 -----> equation A

y=-x+12 ----> equation B

solve the system by graphing

The intersection point is (5.7)

see the attached figure

step 4

we know that

The distance from point P to the the line L is equal to the distance between the point P and point (5,7)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

(2,10) and (5,7)

substitute

d=\sqrt{(7-10)^{2}+(5-2)^{2}}

d=\sqrt{(-3)^{2}+(3)^{2}}

d=\sqrt{18}\ units

simplify

d=3\sqrt{2}\ units

see the attached figure to better understand the problem

6 0
4 years ago
I will give a lot of points to help
Pachacha [2.7K]

Answer + Explanation:

The Monty Hall problem is a famous problem in conditional probability and reasoning using Bayes' theorem.

How to explain the probability?

In the problem, you are on a game show, being asked to choose between three doors. Behind each door, there is either a car or a goat.

You choose a door. The host, Monty Hall, picks one of the other doors, which he knows has a goat behind it, and opens it, showing you the goat.

You know, by the rules of the game, that Monty will always reveal a goat. Monty then asks whether you would like to switch your choice of door to the other remaining door.

In conclusion, the solution is that switching will let you win twice as often as sticking with the original choice.

7 0
2 years ago
what operations would you use in order to solve 3x - 4 = 26. Please write the operations in the order you would use them.
Ratling [72]

Answer:

3x-4=26 |+4

3x=30 |:3 to get clear x

x=10

Hope this helps!!

Step-by-step explanation:

8 0
3 years ago
WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!
umka21 [38]

Relations are subsets of products <span><span>A×B</span><span>A×B</span></span> where <span>AA</span> is the domain and <span>BB</span> the codomain of the relation.

A function <span>ff</span> is a relation with a special property: for each <span><span>a∈A</span><span>a∈A</span></span> there is a unique <span><span>b∈B</span><span>b∈B</span></span> s.t. <span><span>⟨a,b⟩∈f</span><span>⟨a,b⟩∈f</span></span>.

This unique <span>bb</span> is denoted as <span><span>f(a)</span><span>f(a)</span></span> and the 'range' of function <span>ff</span> is the set <span><span>{f(a)∣a∈A}⊆B</span><span>{f(a)∣a∈A}⊆B</span></span>.

You could also use the notation <span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈f</span>]</span>}</span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈f</span>]</span>}</span></span>

Applying that on a relation <span>RR</span> it becomes <span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈R</span>]</span>}</span><span>{b∈B∣∃a∈A<span>[<span>⟨a,b⟩∈R</span>]</span>}</span></span>

That set can be labeled as the range of relation <span>RR</span>.

8 0
3 years ago
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