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cestrela7 [59]
3 years ago
7

There are 14 rows of seats in a cinema.

Mathematics
1 answer:
xeze [42]3 years ago
3 0

Answer:

24 tickets were not sold

Step-by-step explanation:

Here, we want to get the number of unsold tickets

In each row, there are 15 seats

In the Cinema, there are 14 rows

The total number of seats is thus;

15 * 14 = 220 seats

If all the 220 seats were booked, the total amount of ticket sales would have been;

220 * 6.5 = £1430

But in this case, the amount generated is £1,274

Hence, the difference in these amounts will be;

1430 - 1274 = £156

To get the number of tickets unsold, we have to divide the amount here by the price per unit ticket

Mathematically, we have this as;

£156/£6.5 = 24

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Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

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Step-by-step explanation:

Considering the system of the equations

\begin{bmatrix}2x-7y=12\\ -x+15y=-6\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:2x-7y=12

2x-7y+7y=12+7y

2x=12+7y

Divide both sides by 2

\frac{2x}{2}=\frac{12}{2}+\frac{7y}{2}

x=\frac{12+7y}{2}

\mathrm{Subsititute\:}x=\frac{12+7y}{2}

\begin{bmatrix}-\frac{12+7y}{2}+15y=-6\end{bmatrix}

-\frac{12+7y}{2}+15y=-6

\mathrm{Multiply\:both\:sides\:by\:}2

-\frac{12+7y}{2}\cdot \:2+15y\cdot \:2=-6\cdot \:2

-\left(12+7y\right)+30y=-12

-12+23y=-12

-12+23y+12=-12+12

23y=0

\mathrm{Divide\:both\:sides\:by\:}23

\frac{23y}{23}=\frac{0}{23}

y=0

\mathrm{For\:}x=\frac{12+7y}{2}

\mathrm{Subsititute\:}y=0

x=\frac{12+7\cdot \:0}{2}

x=\frac{12}{2}

x=6

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

y=0,\:x=6

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3 years ago
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Step-by-step explanation:

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Evaluate this expression. 5^-3
sweet-ann [11.9K]

Answer:

\Huge \boxed{\frac{1}{125}}

Step-by-step explanation:

<h2>Order of operations</h2>

PEMDAS

Parenthesis, exponent, multiply, divide, add, and subtract from left to right.

Do exponent.

\displaystyle \frac{1}{5^3}

\displaystyle 5^3=5\times5\times5=125

\displaystyle \frac{1}{125}=125

\large \boxed{\frac{1}{125}}, which is our answer.

Hope this helps!

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3 years ago
How to solve this problem?
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