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Alborosie
3 years ago
12

Prove tan(x - (π / 4)) = (sin x – cos x) / (cos x + sin x) by filling in the reasons in the table below.

Mathematics
1 answer:
Mrac [35]3 years ago
8 0

No way to know what reasons you're supposed to choose from...

By definition of tangent,

\tan\left(x-\dfrac\pi4\right)=\dfrac{\sin\left(x-\frac\pi4\right)}{\cos\left(x-\frac\pi4\right)}

The angle sum identities give

\tan\left(x-\dfrac\pi4\right)=\dfrac{\sin x\cos\frac\pi4-\cos x\sin\frac\pi4}{\cos x\cos\frac\pi4+\sin x\sin\frac\pi4}

cos\dfrac\pi4=\sin\dfrac\pi4=\dfrac1{\sqrt2}, so we can cancel those terms to get

\tan\left(x-\dfrac\pi4\right)=\dfrac{\sin x-\cos x}{\sin x+\cos x}

as required.

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Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
4 years ago
Heheh be svdbtjdjsbddb
Dennis_Churaev [7]
Did u type that by mistake
6 0
2 years ago
Read 2 more answers
Expand &amp; simplify <br> 5<br> (<br> p<br> +<br> 6<br> )<br> −<br> 5<br> (<br> p<br> −<br> 2<br> )
HACTEHA [7]

Answer: 0p + 40

Step-by-step explanation:

5p + 30 - 5p + 10

0p + 40

8 0
3 years ago
15. Solve the compound inequality.<br> 5x - 11 &lt; -11 or 4x + 2 &gt; 14
s2008m [1.1K]

Answer:

Step-by-step explanation:

5x −11+11<-11+11

5x<0

5x/5<0/5

x<0

4x+2 -2 >14 -2

4x>12

4x/4>12/4

x>3

there both open not closed

hope this helps

5 0
3 years ago
It is estimated that each guest at a party will eat 2/3 pounds of chocolate. How many guest can be served with 6 pounds of choco
alexdok [17]
In this you have to do 6(total) /(Divided) 2/3. And when you do 6/(2/3) you also have to do KCF(keep, change, flip) and that brings you to 18/2 after multiplying across. So the answer would be 9 people.
6 0
3 years ago
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