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Lady bird [3.3K]
3 years ago
13

What is the Square root of 194

Physics
2 answers:
Serjik [45]3 years ago
7 0

This could have been a beautiful opportunity for you to practice using your calculator. But now, somebody will post the answer, the answer won't benefit you in any way, AND you won't get the calculator practice. Too bad.

Degger [83]3 years ago
5 0

13.9283882772 I hope this helps you!

Glad to help you!

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the volume of ice block is 2400cm^3 and its density is 0.9 g/cm^3. how much part of it remains above the surface of water when i
stiks02 [169]

Answer:

240 cm³

Explanation:

Weight = Buoyancy

mg = ρVg

m = ρV

(0.9 g/cm³ × 2400 cm³) = (1 g/cm³) V

V = 2160 cm³

The submerged volume is 2160 cm³, so the volume above the surface is 240 cm³.

4 0
3 years ago
Calculate the magnitude of the gravitational force exerted by the Moon on a 79 kg human standing on the surface of the Moon. (Th
Luden [163]

Answer:

F= 134.92 N

Explanation:

Given that

The mass of the moon ,M = 7.4 x 10²² kg

The mass of the man ,m = 79 kg

The radius ,R= 1.7 x 10⁶ m

The force exerted by moon is given as

F=G\dfrac{Mm}{R^2}

Now by putting the values in the above equation we get

F=6.67\times 10^{-11}\times \dfrac{79\times 7.4\times 10^{22}}{(1.7\times 10^6)^2}\ N\\F=134.92 N

Therefore the force will be 134.92 N.

F= 134.92 N

8 0
4 years ago
A merry-go-round accelerating uniformly from rest achieves itsoperating speed of 2.5rpm in five revolution.
g100num [7]

Answer:

(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²

(B) Time of motion 240.2 s

Explanation:

Given;

final angular speed, ωf = 2.5 RPM

angular distance, θ = 5 rev = 5 x 2π = 10π rad

initial angular speed, ωi = 0

final angular speed in rad/s;

\omega_f = \frac{2.5 \ rev}{min} \times \ \frac{2\pi}{1 \ rev} \times \ \frac{1 \min}{60 s} = 0.2618 \ rad/s \\

(A) the magnitude of its angular acceleration(rad/s^2);

\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\(0.2618)^2 = 0 + (2\times 10\pi)\alpha\\\\0.0685 = 20\pi \alpha\\\\\alpha = \frac{0.0685}{20\pi} \\\\\alpha = 1.09\times 10^{-3} \ rad/s^2

(B) Time of motion;

\omega_f = \omega_i + \alpha t\\\\0.2618 = 0 + 1.09\times 10^{-3} t\\\\t = \frac{0.2618}{1.09\times 10^{-3}} \\\\t = 240.2 \ s

7 0
3 years ago
Match the word to the sentence in which the word is missing. Question 1 options: daughter isotope nuclear fission radiometric da
ella [17]

Answer:

thats to much sauce

Explanation:

5 0
3 years ago
A 40-N force acts on an 80-kg object, initially moving at 20 m/s. How far will the object travel in the next five seconds?
MakcuM [25]

Answer:

106.25 m

Explanation:

Acceleration a = force / mass

= 40 / 80 = 0.5 m /s²

initial velocity u = 20 m /s

a = 0.5 m /s²

time t = 5 s

displacement s = ?

s = ut + 1/2 a t²

= 20 x 5 + .5 x .5 x 5²

= 100 + 6.25

= 106.25 m .

6 0
3 years ago
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