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3 years ago

Ocean waves with a wavelength of 120 m are coming in at a rate of 8 per minute. What is their speed?

Physics

1 answer:

AlekseyPX3 years ago

6 0

Explanation:

We know that,

$v(wave \: speed) = f(frequency) \times \alpha (wavelength)$

frequency (f) = 1 / t (sec) = 8/60 = 0.13 Hz

V ( wave speed) = 0.13 * 120 = 16 m/sec

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If the coefficient of static friction between your coffee cup and the horizontal dashboard of your car is µs = 0.800, how fast c

Cloud [144]

Answer:

Before start of slide velocity will be 14.81 m/sec

Explanation:

We have given coefficient of static friction $\mu =0.8$

Angle of inclination is equal to $\Theta =tan^{-1}\mu$

$\Theta =tan^{-1}0.8=38.65^{\circ}$

$tan{38.65^{\circ}}=0.8$

Radius is given r = 28 m

Acceleration due to gravity $g=9.8m/sec^2$

We know that $tan\Theta =\frac{v^2}{rg}$

$0.8=\frac{v^2}{28\times 9.8}$

$v^2=219.52$

$v=14.816m/sec$

So before start of slide velocity will be 14.81 m/sec

3 0

3 years ago

Which of these statements about resistance is true? Choose the best answer.

bonufazy [111]

'C' and 'D' are the same statement, and none of the 3 choices
is good.

Electrical energy is produced in a generator, a solar panel, or
a battery, not in things with resistance.

From the generator or battery, current flows through a circuit of
one or more components.

The greater the resistance of a component, the more energy is
LOST as the current flows through it. The component dissipates
the energy in the form of heat.

8 0

3 years ago

Read 2 more answers

The current in the wires of a circuit is 180.0 milliAmps. If the

Virty [35]

Explanation:

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4 0

3 years ago

A basketball player throws the ball at a 47 angle above the horizontal to a hoop which is located a horizontal distance L = 5.0

FromTheMoon [43]

Answer:

$v_0 =$ 1.71

Explanation:

the parabolic movment is described by the following equation:

$y = tan(a)x-\frac{1}{2v_0^2(cos(a))^2}gx^2$

where y is the height of the ball, a is the angle of launch, $v_0$ the initial velocity, g the gravity and x is the horizontal distance of the ball.

So, if we want that the ball reach the hood, we will replace values on the equation as:

$0.8 = tan(47)(5)-\frac{1}{2v_0^2(cos(47))^2}(9.8)(5)^2$

Finally, solving for $v_0$ , we get:

$v_0=\sqrt{\frac{-9.8(5)^2}{(0.8-tan(47)(5))2cos^2(47)}}$

$v_0 =$ 1.71

4 0

4 years ago

The elevator accelerates upward (in the positive direction) from rest at a rate of 1.95 m/s2 for 2.15 s. Calculate the tension i

sammy [17]

The mass is missing. The mass of the elevator is 1650 kg.

Answer:

The tension in the cable is 19387.5 N.

Explanation:

Given:

Initial velocity of the elevator (u) = 0 m/s

Acceleration in the upward direction (a) = 1.95 m/s²

Time taken by the elevator (t) = 2.15 s

Mass of the elevator and persons (m) = 1650 kg

Let the tension in the cable wire be 'T' Newtons.

Now, there are 2 forces acting in the vertical direction. One is tension in the upward direction and the other the weight of the elevator in the downward direction.

As the elevator is accelerating upward, the net force acts in the upward direction.

So, net force on the elevator is given as:

$F_{net}=T-mg$

Now, from Newton's second law, net force equals mass times acceleration.

$F_{net}=ma\\\\T-mg=ma\\\\T=m(g+a)$

Plug in the given values and solve for 'T'. This gives,

$T=1650\ kg(9.8+1.95)\ m/s^2\\\\T=1650\times11.75\ N\\\\T=19387.5\ N$

Therefore, the tension in the cable is 19387.5 N.

3 0

4 years ago