Ask question

Ask question

All categories

3 years ago

7

Cosine, tangent, and sine (topic) how do you solve this (work shown please)

1 answer:

damaskus [11]3 years ago

3 0

Sine θ = $\frac{opposite}{hypotenuse}$
Cosine θ = $\frac{adjacent}{hypotenuse}$
Tangent θ = $\frac{opposite}{adjacent}$

∴ $Sin x = \frac{e}{f}$
$Cos x = \frac{d}{f}$
$Tan x = \frac{e}{d}$

You might be interested in

Here is a picture of a cube, and the net of this cube. What is the surface area of this cube? Enter your answer in the box. mm²

UNO [17]

you times everything by 2 and get 144+16+1=161 milliliters i hope this helped have a great day

6 0

3 years ago

Read 2 more answers

Quadrilateral PQRS with diagonals PR and SQ that intersect at point T

larisa [96]

Answer:

A. segment PS ≅ segment QR

Step-by-step explanation:

Given that the quadrilateral PQRS is a rectangle then;

The diagonals are PR and SQ
Point of intersection of diagonals is T
Segment PS≅ Segment QR
∠PSQ≅ ∠SQR
segment SR≅ segment PQ

8 0

3 years ago

Read 2 more answers

A train left a station at 8:13 a.m. arriving at its destination at 4:52 p.m. If the stations are 527.65 miles apart, calculate t

Tomtit [17]

9514 1404 393

Answer:

D. 61 mi/h

Step-by-step explanation:

The travel time is 16:52 -8:13 = 8:39 hours, or 8.65 hours. Then the speed is ...

speed = distance/time = 527.65 mi/(8.65 h) = 61 mi/h

_____

<em>Additional comment</em>

It is often convenient to use "military" or "24-hour" time for calculations of time periods that extend over noon or midnight. For this purpose, 12 gets added to the hour number in the afternoon (pm). Of course, 39 minutes is 39/60 hours. That is found to be 0.65 hours by performing the division of 39 by 60.

6 0

2 years ago

Mario is constructing a square dart board. It will consist of a smaller square centered in a larger square. The smaller square m

Ivan

Answer:

6 inches.

Step-by-step explanation:

Let a represent side length of larger square.

We know that area of square is square of its side length, so area of the larger square will be $a^2$ .

The area of smaller square would be $4^2$ .

We will use proportions to solve our given problem.

$\frac{\text{Area of smaller square}}{\text{Area of larger square}}=\frac{4}{9}$

$\frac{4^2}{a^2}=\frac{4}{9}$

$\frac{16}{a^2}=\frac{4}{9}$

Cross multiply:

$4*a^2=16*9$

$\frac{4*a^2}{4}=\frac{16*9}{4}$

$a^2=36$

Take square root:

$a=\pm\sqrt{36}$

$a=\pm 6$

Since the length cannot be negative, therefore, the side length of larger square is 6 inches.

8 0

2 years ago

The minimum takeoff speed for a certain airplane is 75 m/s. What minimum acceleration is required if the plane must leave a runw

chubhunter [2.5K]

The solution is in the attachment

5 0

2 years ago

Read 2 more answers