Angle B measures 60. What is the measure of the angle that is complementary to angle B ?

Mathematics

2 answers:

MaRussiya [10]3 years ago

8 0

120 degrees
(180-60=120)

MArishka [77]3 years ago

4 0

Answer: 30*

Step-by-step explanation:

Complementary angles add up to 90*

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Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or

WARRIOR [948]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8$

compare them away.

4 0

3 years ago

A circular mirror has the diameter of 12 inches. what is the area in square inches?

nika2105 [10]

Hello!

To find the area of a circle you do $\pi r^{2}$

Where r stands for radius.

The radius is just half the diameter

So you put that into a calculator and get 113.1 $in^{2}$

Hope this helps!

5 0

4 years ago

The sum of the digits of a two-digit number is 8. The difference between the number and the reversed number is 10 more than the

Vesna [10]

Answer:

The number is 62

Step-by-step explanation:

Let the digits of the number be T and U;

A 2 digit number is represented as: 10T + U

So,

$T + U = 8$