Let the given complex number
z = x + ix = 
We have to find the standard form of complex number.
Solution:
∴ x + iy =
Rationalising numerator part of complex number, we get
x + iy = 
⇒ x + iy = 
Using the algebraic identity:
(a + b)(a - b) = 
- 
⇒ x + iy = 
⇒ x + iy = 
[ ∵ 
]
⇒ x + iy = 
⇒ x + iy = 
⇒ x + iy = 
⇒ x + iy = 1 - i
Thus, the given complex number in standard form as "1 - i".
i uploaded a vid on this here
https://www.you tube.com/watch?v=dQw4w9WgXcQ
Answer: (x)(x)(x) = x^3.
Step-by-step explanation:
x^3 means multiply x by it's self 3 times.
Hope this helps..
Answer:
Y=7+3x, x=-3, y=-2
Step-by-step explanation:
3x-5y=1. Equation 1
3x-y=-7. Equation 2
-y=-7-3x isolate for y in equation 2
y=7+3x multiplied by -1 to get positive y
3x-5(7+3x)=1 substitute y value of equation 2 (7+3x) into equation 1
3x-35-15x=1
-12x=36
x=-3
solve for y.
3x-5y=1
3(-3)-5y=1
-9-5y=1
-5y=10
y=-2
I'm guessing 99.65
1800+10%-20%-25%=99.65
but it probably wrong
