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3 years ago

14

I need help fast pls

1 answer:

Svetach [21]3 years ago

7 0

The area of a parallelogram = base(b) × height(h)

Here the base value = 12.0 in

while the value of the height is not given but the angle of the base with it adjacent side is given that is here 45°

Let the magnitude of height or altitude be x

So the value of x can be find out by trigonometry

Here we can write tan(45°) = x/6.5 in

then the value of tan(45°) = 1

so 1 × 6.5 = x

therefore the value of x= 6.5

Now we can find the area of the parallelogram such that base × height = (6.5×12) in^2 = 78.0 in^2 (ans)

Hope it helps

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3 years ago

Let x^2 + 11x = 3

Serggg [28]

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3 years ago

Read 2 more answers

Solve the equation for all values of x.<br> (8x+9)(49x^2-100)=0

Liono4ka [1.6K]

Answer:

$x = \frac{-9}{8} , \frac{-10}{7} , \frac{10}{7}$

Step-by-step explanation:

8x+9=0

8x=-9

$x = \frac{-9}{8}$

or

$49x^{2}-100 = 0$

$(7x)^{2} -10^{2} =0$ ,

$(7x+10)(7x-10)=0$

$7x+10=0, 7x-10=0$

$7x=-10, 7x=10$

$x=-\frac{-10}{7}$ , $x = \frac{10}{7}$

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2 years ago

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3 years ago

Place the three functions in order from the fastest decreasing average rate of change to the slowest decreasing average rate of

victus00 [196]

Answer:

g(x), f(x) and h(x)

Step-by-step explanation:

Given

Interval: (0,3)

See attachment for functions f(x), g(x) and h(x)

Required

Order from fastest to slowest decreasing average rate of change

The average rate of change is calculated as:

$Rate = \frac{f(b) - f(a)}{b - a}$

In this case:

$(a,b) = (0,3)$

i.e.

$a = 0\\b=3$

For f(x)

$f(x) = 16(\frac{1}{2})^x$

$Rate = \frac{f(b) - f(a)}{b - a}$

$Rate = \frac{f(3) - f(0)}{3 - 0}$

$Rate = \frac{f(3) - f(0)}{3}$

Calculate f(3) and f(0)

$f(x) = 16(\frac{1}{2})^x$

$f(3) = 16(\frac{1}{2})^3 = 16 * \frac{1}{8} = 2$

$f(0) = 16(\frac{1}{2})^0 = 16 * 1 = 16$

So:

$Rate = \frac{f(3) - f(0)}{3}$

$Rate = \frac{2 - 16}{3}$

$Rate = -\frac{14}{3}$

For g(x)

$Rate = \frac{g(b) - g(a)}{b - a}$

$Rate = \frac{g(3) - g(0)}{3 - 0}$

$Rate = \frac{g(3) - g(0)}{3}$

From the table of g(x)

$g(3) = 1$

$g(1) = 27$

So:

$Rate = \frac{1 - 27}{3}$

$Rate = -\frac{26}{3}$

For h(x)

$Rate = \frac{h(b) - h(a)}{b - a}$

$Rate = \frac{h(3) - h(0)}{3 - 0}$

$Rate = \frac{h(3) - h(0)}{3}$

From the graph of h(x)

$h(3) = -3$

$h(0) = 4$

So:

$Rate = \frac{-3 - 4}{3}$

$Rate = -\frac{7}{3}$

So, the calculated rates of change are:

$f(x) = -\frac{14}{3}$ $= -4.67$

$g(x) = -\frac{26}{3}$ $=-8.67$

$h(x) = -\frac{7}{3}$ $=-2.33$

By comparison:

From the fastest decreasing to slowest, the order is: <em>g(x), f(x) and h(x)</em>

4 0

3 years ago