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3 years ago

Which sentence contains an inappropriate shift in tense?

1 answer:

Montano1993 [528]3 years ago

7 0

C. Hummingbirds are hovering over the geraniums while caterpillars munched leaves.

This is because the tense of the hummingbirds is in the "ing" form, while the tense of the caterpillars is in past tense, or the "ed" form. Because these tenses do not agree, it is an inappropriate shift in verb tense.

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A recreation center offers a membership for $75.Members may take classes for $10 each.Nonmembers pay $15 for these classes.how m

antoniya [11.8K]

75 +10n = 15n
75 = 5n
15 = n

Therefore 15 classes

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3 years ago

Which ordered pairs in the form (x, y) are solutions to the equation

Levart [38]

The answer is a and c

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2 years ago

Which is an example of continuous data? A) numbers on the face of a clock B) number of peers on a jury C) time it takes to showe

oee [108]

Answer: C

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Continuous Data means there is no set or certain time.So like a shower, you can take however long you want.

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3 years ago

Read 2 more answers

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65* It is drawn with a round ruller...

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3 years ago

At the Foremost State Bank the average savings account balance in 2012 was $1900. A random sample of 45 savings account balanes

lakkis [162]

Answer:

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step-by-step explanation:

Step(i):-

Mean of the Population = 1900

Given random sample size 'n' = 45

Mean of the sample x⁻ = 1000

Standard deviation of the sample = 225

Null Hypothesis:-

There is no difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012.

Alternative Hypothesis :-

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step(ii):-

Test statistic

$t = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$t = \frac{1000-1900 }{\frac{225}{\sqrt{45} } }$

t = -900 /33.54 = -26.517

|t| = |-26.517|=26.517

Degrees of freedom

γ = n-1 = 45-1 =44

t₍₀.₀₁ , ₄₄₎ = 2.326

The calculated |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

4 0

2 years ago