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spin [16.1K]
3 years ago
15

in how many ways cvan 5 people be chosen and arranged in a straight line, if there are 6 people to choose from'

Mathematics
1 answer:
9966 [12]3 years ago
8 0

Answer:

<h3>720 different ways</h3>

Step-by-step explanation:

Permutation has to do with arrangement. If r objevt selected from n pool of objects are to be arranged in a straight line, this can be done in nPr number of ways.

nPr = n!/(n-r)!

If 5 people are to be chosen and arranged in a straight line, if there are 6 people to choose from, this can be done in  6P5 numbe of ways.

6P5 = 6!/(6-5)!

6P5 = 6!/1!

6P5 = 6*5*4*3*2*1

6P5  = 720 different ways

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kap26 [50]

Answer:

Addition is...

1+1 = 2

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4 0
4 years ago
Please help will give Brianliest!!!
marshall27 [118]

Answer: y=2(x-3)-5

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8 0
3 years ago
What's the surface area rounded to the hundredth place
marysya [2.9K]

Answer:

Step-by-step explanation:

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3 years ago
A set of cards includes 20 yellow cards, 16 green cards, and 24 blue cards. What is the probability that a blue card is chosen a
baherus [9]

Answer:

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7 0
3 years ago
Adult tickets to the fall play cost $8 and student tickets cost $4. the drama class sold 20 more adult tickets than student tick
Ganezh [65]
Let a = Adult tickets, s = Student tickets; we are going to set up a system of equations. 

8a + 4s = 880
a - s = 20

We are going to multiply the second equation by so that we can cancel out one of the variables and solve for the other. This gives you:

8a + 4s = 880
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Notice the s-variables will cancel:

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Now we plug in the amount of adult tickets to solve for the student ones.

75 - s = 20
- s = - 55

Divide both sides by - 1
s = 55.

There were 55 student tickets sold and 75 adult tickets. 


6 0
3 years ago
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