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spin [16.1K]
3 years ago
15

in how many ways cvan 5 people be chosen and arranged in a straight line, if there are 6 people to choose from'

Mathematics
1 answer:
9966 [12]3 years ago
8 0

Answer:

<h3>720 different ways</h3>

Step-by-step explanation:

Permutation has to do with arrangement. If r objevt selected from n pool of objects are to be arranged in a straight line, this can be done in nPr number of ways.

nPr = n!/(n-r)!

If 5 people are to be chosen and arranged in a straight line, if there are 6 people to choose from, this can be done in  6P5 numbe of ways.

6P5 = 6!/(6-5)!

6P5 = 6!/1!

6P5 = 6*5*4*3*2*1

6P5  = 720 different ways

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Based on the picture..Find the area in terms of xFind the perimeter in terms of x
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The area of a rectangle is given by the product of its dimensions.

If this rectangle has a length of 2x + 7 and a width of x + 4, its area is:

\begin{gathered} \text{Area}=\text{length}\cdot\text{width} \\ \text{Area}=(2x+7)(x+4)_{} \\ \text{Area}=2x^2+8x+7x+28 \\ \text{Area}=2x^2+15x+28 \end{gathered}

The perimeter is the sum of all side lengths, so we have:

\begin{gathered} \text{Perimeter}=(2x+7)+(x+4)+(2x+7)+(x+4) \\ \text{Perimeter}=6x+22 \end{gathered}

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3 years ago
Rebecca’s boss pays her time and a half for overtime work. If her regular wage is $13.50 per hour, what is her overtime rate?
valentina_108 [34]

Answer: 20.25

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5 0
3 years ago
Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3
babymother [125]

Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

Given:

3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable z first.

Step 1:  She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9

Now, adding this to equation 1 will cancel out z terms.

12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4

Now, she need to make one more equation in x\ and \ y.

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21

Now, adding this to equation 2 will not cancel out z terms.

-28x+28y+7z+7x+y+7z=21-1\\(-28x+7x)+(28y+y)+(7z+7z)=20\\-21x+29y+14z=20

So, she makes mistake in step 2 as the z terms are not being cancelled.

6 0
3 years ago
Read 2 more answers
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