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3 years ago

Write one-half times a number minus 4. use x as a variable

Mathematics

2 answers:

alexdok [17]3 years ago

8 0

Answer:

$\frac{1}{2}$ x-4

Step-by-step explanation:

Nina [5.8K]3 years ago

3 0

Answer:

1/2 (x)-4

Step-by-step explanation:

Hopes this helps

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Two companies rent moving trucks. Pack and Go charges a $39.95 flat fee, and $0.45 for every mile driven. U-Drive charges a $59.

Kisachek [45]

Answer:

The indifference point is 200 miles

Step-by-step explanation:

<u>First, we need to establish the total cost formula for each company:</u>

Pack and Go:

Total cost= 39.95 + 0.45x

x= miles driven

U-Drive:

Total cost= 59.95 + 0.35x

x= miles driven

<u>Now, we equal both formulas and isolate x:</u>

39.95 + 0.45x = 59.95 + 0.35x

0.1x = 20

x= 200 miles

The indifference point is 200 miles

4 0

3 years ago

26. Define a relation ∼ ∼ on R 2 R2 by stating that ( a , b ) ∼ ( c , d ) (a,b)∼(c,d) if and only if a 2 + b 2 ≤ c 2 + d 2 . a2+

Tresset [83]

Answer:

~ is reflexive.

~ is asymmetric.

~ is transitive.

Step-by-step explanation:

~ is reflexive:

i.e., to prove $\forall (a, b) \in \mathbb{R}^2$ , $(a, b) R(a, b)$ .

That is, every element in the domain is related to itself.

The given relation is $\sim: (a,b) \sim (c, d) \iff a^2 + b^2 \leq c^2 + d^2$

Reflexive:

$(a, b) \sim (a, b)$ since $a^2 + b^2 = a^2 + b^2$

This is true for any pair of numbers in $\mathbb{R}^2$ . So, $\sim$ is reflexive.

Symmetry:

$\sim$ is symmetry iff whenever $(a, b) \sim (c, d)$ then $(c, d) \sim (a, b)$ .

Consider the following counter - example.

Let (a, b) = (2, 3) and (c, d) = (6, 3)

$a^2 + b^2 = 2^2 + 3^2 = 4 + 9 = 13$

$c^2 + d^2 = 6^2 + 3^2 = 36 + 9 = 42$

Hence, $(a, b) \sim (c, d)$ since $a^2 + b^2 \leq c^2 + d^2$

Note that $c^2 + d^2 \nleq a^2 + b^2$

Hence, the given relation is not symmetric.

Transitive:

$\sim$ is transitive iff whenever $(a, b) \sim (c, d) \hspace{2mm} \& \hspace{2mm} (c, d) \sim (e, f)$ then $(a, b) \sim (e, f)$

To prove transitivity let us assume $(a, b) \sim (c, d)$ and $(c, d) \sim (e, f)$ .

We have to show $(a, b) \sim (e, f)$

Since $(a, b) \sim (c, d)$ we have: $a^2 + b^2 \leq c^2 + d^2$

Since $(c, d) \sim (e, f)$ we have: $c^2 + d^2 \leq e^2 + f^2$

Combining both the inequalities we get:

$a^2 + b^2 \leq c^2 + d^2 \leq e^2 + f^2$

Therefore, we get: $a^2 + b^2 \leq e^2 + f^2$

Therefore, $\sim$ is transitive.

Hence, proved.

3 0

3 years ago

PLEASE HELP THANK YOU !!!!!!!

Fantom [35]

Answer:

Pretty sure c is your correct answer :)

Step-by-step explanation:

I hope this helps :)

5 0

3 years ago

Find the length x and y please

Artemon [7]

Answer:

Step-by-step explanation:

To find the x-intercept using the straight-line equation, substitute y=0 and solve for x. To find the y-intercept, substitute x=0 and solve for y.

7 0

2 years ago

Phillip watched a beach volleyball game from 1:45pm to 2:00pm. how many degrees did the minute hand turn?

S_A_V [24]

it turned 90° clockwise

Step-by-step explanation:

if you look on a clock or watch face 45 minutes to o'clock is a quarter of the whole face. there are 360° in a circle and a quarter of that is 90°

3 0

3 years ago

Read 2 more answers