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3 years ago

Write one-half times a number minus 4. use x as a variable

Mathematics

2 answers:

alexdok [17]3 years ago

8 0

Answer:

$\frac{1}{2}$ x-4

Step-by-step explanation:

Nina [5.8K]3 years ago

3 0

Answer:

1/2 (x)-4

Step-by-step explanation:

Hopes this helps

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Andre45 [30]

Use MATH-WAY it has all the answer

4 0

3 years ago

Khan academy : Sasha has been saving the money she earns from babysitting for several months. She has a total of $96.75 dollar s

AVprozaik [17]

Answer:

$100.00

Step-by-step explanation:

If we are rounding to the nearest 10, then we only have to look at 96. Since 6 is bigger than 5, we round up to 100.

6 0

3 years ago

Which of the following addition problems yields a sum that is an irrational number? Select TWO that apply. 23+97 2√+2√ 32+25√ 4√

GuDViN [60]

Answer:

28n 72uwbs jsjsbkajskld

5 0

3 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

Mrs. Vanwhy made a two-way table to show which students made honor roll and which students study a foreign language.

lara31 [8.8K]

Answer:

Its the 2nd table.

7 0

3 years ago

Read 2 more answers