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2 years ago

How to put 5.5÷5 in a model

1 answer:

4 0

This answer is 1.1.

It is because:

5 goes into 5.5 ... 1.1 time. You would divide each 5 by 5 and then put the decimal in the middle.

On a model it would be something like this, 5 sections of 100 and 10 combined together.

Take a closer look!

Draw 6 100 by 100 graphs,

Color in 5 and 50 hundredths of the models.

Divide the colored sections by 1 and 10 hundredths.

Key:

The models are the 6 squares.

The 5.5 is the color red

The black is the division of 1.1

Hope this helps:

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What is 6.08 X 10 to the -12 power

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6.08x10^-12
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Pedro opened his account with $680 and withdrew $35 per week. Maria opened her account with $570 and withdrew $25 per week. Solv

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Answer:

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Step-by-step explanation:

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3 years ago

What is the answer to this math question “X - 3 = 6”

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Answer: x = 9

Step-by-step explanation:

x can be equal to 9.

Lets plug in 9 to the variable x, in this equation, x -3 = 6.

x - 3 = 6

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2 years ago

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3 years ago

The National Transportation Safety Board publishes statistics on the number of automobile crashes that people in various age gro

ra1l [238]

Answer:

a) Null hypothesis: $p\leq 0.12$

Alternative hypothesis: $p > 0.12$

b) $z_{\alpha}=1.64$

c) $z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

d) $p_v =P(z>1.362)=0.0866$

e) For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

Step-by-step explanation:

Information given

n=1000 represent the random sample selected

X=134 represent the number of young drivers ages 18 – 24 that had an accident

$\hat p=\frac{134}{1000}=0.134$ estimated proportion of young drivers ages 18 – 24 that had an accident

$p_o=0.12$ is the value that we want to verify

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic

$p_v{/tex} represent the p valuePart aWe want to verify if the population proportion of young drivers, ages 18 – 24, having accidents is greater than 12%: Null hypothesis:[tex]p\leq 0.12$

Alternative hypothesis: $p > 0.12$

The statistic would be given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Part b

For this case since we are conducting a right tailed test we need to find a critical value in the normal standard distribution who accumulates 0.05 of the area in the right and we got:

$z_{\alpha}=1.64$

Part c

For this case the statistic would be given by:

$z=\frac{0.134 -0.12}{\sqrt{\frac{0.12(1-0.12)}{1000}}}=1.362$

Part d

The p value can be calculated with the following probability:

$p_v =P(z>1.362)=0.0866$

Part e

For this case since the statistic is lower than the critical value and the p value higher than the significance level we have enough evidence to FAIL to reject the null hypothesis so then we don't have information to conclude that the true proportion is higher than 0.12

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2 years ago