The price of the sweater was reduced by 40%
Step-by-step explanation:
Step 1; Cost before reduction was $20. The cost after reduction was 12$. Cost reduced= cost before reduction - cost after reduction
Cost reduced= $20 - $12 = $8
Step 2; We must find how much of the cost was reduced from the initial cost i.e. how much $8 is to $20. To do this we must convert it into a percentage. We divide the $8 with the $20 to get a value. This value must be multiplied with a 100 to be converted into a percentage.
Cost by which sweater was reduced=
* 100 = 0.4 * 100 = 40
So the price of the sweater was reduced from $20 to $8 which equates to a reduction in 40%.
The ordered pair (6 , 4) is a solution for y - 4 = 7(x - 6)
Step-by-step explanation:
The point-slope form of a linear equation is:
, where
- m is the slope of the line
is a point on the line
Any point on the line is a solution for the equation of the line
The solution of an equation is the values of x and y which make the left hand side is equal to the right hand side
∵ The equation is y - 4 = 7(x - 6)
- Compare the equation by the point-slope form above
∴ m = 7
∴
= 6 and
= 4
- That means point (6 , 6) lies on the line
∴ Point (6 , 4) is a point on the line which represents the
given equation
∵ Any point on a line is a solution of the equation of that line
∴ (6 , 4) is a solution of the equation
The ordered pair (6 , 4) is a solution for y - 4 = 7(x - 6)
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Answer:
<h2>corresponding angles</h2>
Hope this helps
On 3 and 6 you did not clarify whether it is addition, subtraction, multiplication, or division.
Therefore, I have worked out all possible solutions.
If 2(3 - 6 x 3 - 5) then the solution is 12.<span>
If 2(3 + 6 x 3 - 5) then the solution is -36.</span><span>
If 2(3 / 6 x 3 - 5) then the solution is -2.
If 2(3 x 6 x 3 - 5) then the solution is -72.</span>
Answer:
a. i. x ≤ 25 ii. 16 < x < 35 iii. 25 < x ≤ 95
b. The second and third car seats are appropriate for a 35 lb child.
Step-by-step explanation:
a. Model those ranges with compound inequalities
Let x represent the car seat.
i. A car seat designed for a child weighing up to and including 25 lb is described by the inequality.
x ≤ 25
ii. A car seat designed for a child weighing between 16 lb and 35 lb is described by the inequality.
16 < x < 35
iii. A car seat designed for a child weighing between 25 lb and 95 lb inclusive is described by the inequality.
25 < x ≤ 95
b. Which car seats are appropriate for a 33-lb child?
Since 35 lb is included in the range of the inequalities for the second and third card seats, the second and third car seats are appropriate for a 35 lb child.