Answer:
The t distribution is used, because we have the standard deviation for the sample.
Step-by-step explanation:
When to use the z or the t distribution?
When we have the standard deviation for the population, we use the z distribution.
When we have the standard deviation for the sample, we use the t distribution.
In this question:
We have the standard deviation for the sample, which means that the t distribution is used.
Answer:
one solution the have a point trust me a
Answer:
1. 
2. ![x=\pm7i[tex]3.[tex]\pm 12x =a](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fp%3E%3Cp%3E3.%5Btex%5D%5Cpm%2012x%20%3Da)
4. 22
Step-by-step explanation:
1. 



2. 


![x=\pm7i[tex]3. Area of square = [tex]a^{2}](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E3.%20Area%20of%20square%20%3D%20%5Btex%5Da%5E%7B2%7D)
Where a is the side
We are given an area o square = 
So, 


4. We are given that the solution of quadratic equation -9 and 9
So, equation becomes:


So, in the given equation 
z should be the number from which if we subtract 103 so we get 81
Substitute z = 22



Thus the value of z is 22

We know that
and 
Substitute in the value. 
Use a calculator to multiply. 
Answer:
−
4x−2
Step-by-step explanation: