Answer:
Reference angle will be 30°
sin(330°) will be equal to 
cos(330°) will be equal to 0.866
Step-by-step explanation:
We have given angle is 330°
As the angle 
is in forth quadrant
We know that in forth quadrant the reference angle is given by
Reference angle 
As the angle is 330°
So the reference angle will be 
Now we have to find the value of
sin(330°) 
And now 
The first thing in the reason column of a two colum proof is always GIVEN as it always coincide with an established fact which has been stated in the question to be worked on.
Two colum proofs involves using a tabulated format in establishing a conjecture.
Statements or facts are written on one side and the reason why the statement is true is stated in the reason column which is on the opposite side.
Starting a two column proof usually involve stating the the assumptions which are given about the shape or geometry.
Since each statement made requires a reason, then the reason behind the first statement which is based on what is stated in the question is written as GIVEN.
THEREFORE, after the statement given in the question has been established, then other reasons such as distributive, Commutative and other reasons may be used to proof one's solution statement.
Learn more :brainly.com/question/22172471
Answer:
75° degree angle
Step-by-step explanation:
Since the angle 105° is in the second quadrant, subtract 105° from 180° .
180-105=75
524 cm cubed
Explanation: 4/3 x pi x 5cubed = 523.599cm cubed rounded to 524cm cubed
Answer:
The mean is also increased by the constant k.
Step-by-step explanation:
Suppose that we have the set of N elements
{x₁, x₂, x₃, ..., xₙ}
The mean of this set is:
M = (x₁ + x₂ + x₃ + ... + xₙ)/N
Now if we increase each element of our set by a constant K, then our new set is:
{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}
The mean of this set is:
M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N
M' = (x₁ + x₂ + ... + xₙ + N*k)/N
We can rewrite this as:
M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N
and (x₁ + x₂ + ... + xₙ)/N was the original mean, then:
M' = M + (k*N)/N
M' = M + k
Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.
