Answer:
Attached is the complete working. Hope it helps.
Answer:-2
explanation:
substitute - 4 into q(x)
Add three on both sides
Multiply both sides by...
Answer:
c
Step-by-step explanation:
Find your x and y intercepts. Once you have those 2 points you can connect them. Use a test point, a point that is not on the line to see what side you're shading. If your test point proves that the equation is false, you shade away from your line. If it's true to shade towards your line.
Answer:
C). sign chart; zeroes
Step-by-step explanation:
A function potentially changes sign at each of its <em>zeros</em> and vertical asymptotes. So, to fill out a <em>sign chart</em>, you need to determine what the sign is on either side of each of these points. You can do that using test numbers, or you can do it by understanding the nature of the zero or asymptote.
<u>Examples:</u>
f1(x) = (x -3) . . . . changes sign at the zero x=3. Is positive for x > 3, negative for x < 3.
f2(x) = (x -4)^2 . . . . does not change sign at the zero x=4. It is positive for any x ≠ 4. This will be true for any even-degree binomial factor.
f3(x) = 1/(x+2) . . . . has a vertical asymptote at x=-2. It changes sign there because the denominator changes sign there.
f4(x) = 1/(x+3)^2 . . . . has a vertical asymptote at x=-3. It does not change sign there because the denominator is of even degree and does not change sign there.
