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11111nata11111 [884]

3 years ago

10

Demont used 4 gallons of gasoline in three days driving to work .Each day he used the same amount of gasoline. How many gallons

of gasoline did he use each day?

1 answer:

ikadub [295]3 years ago

5 0

Answer:

1 1/3 gallons per day

Step-by-step explanation:

To find <em>gallons per day</em>, divide gallons by days. ("per" means "divided by")

(4 gal)/(3 day) = (4/3) gal/day

Demont used 4/3 = 1 1/3 gallon each day.

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frez [133]

Answer:

131.625 is your answer

Step-by-step explanation:

3 0

3 years ago

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Misha Larkins [42]

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3 0

3 years ago

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

5 0

3 years ago

Read 2 more answers

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nataly862011 [7]

I think it may be that the train is going too fast zoom km 1600 km at the end

5 0

3 years ago

Can anyone help me please

Ipatiy [6.2K]

Answer:

Step-by-step explanation:

We need to check each u value to say if each one is correct...

8 $\leq$ u - 27

when u = 33

8 $\leq$ 33 - 27

8 $\leq$ 6

and it's true!

So, 33 is solution

when u = 39

8 $\leq$ 39 - 27

8 $\leq$ 12

It isn't true. No solution!

When u = 31

8 $\leq$ 31 - 27

8 $\leq$ 4

It's true and it also is a solution.

when u = 35

8 $\leq$ 35 - 27

8 $\leq$ 8

it's true and it also is a solution.

4 0

3 years ago