yo sup??
mid point of circle=centre of circle
let centre be O(3,2)
and the point be P(-4,8) and the other point be Q(x,y)
by mid point formula
-4+x/2=3 and 8+y/2=2
x=10 and y=-4
therefore coordinates of the other point are (10,-4)
Hope this helps.
Use Pythagorean theorem.
[tex]|ON|^2+|MN|^2=|OM|^2\\\\x^2+x^2=8^2\\\\2x^2=64\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=32\to x=\sqrt{32}\\\\x=\sqrt{16\cdot2}\\\\x=\sqrt{16}\cdot\sqrt2\\\\\boxed{x=4\sqrt2}
Answer: |MN| = 4√2.
Answer: 8:05
Step-by-step explanation:
Answer:
g(x) = x^2 -6x +9
Step-by-step explanation:
A function f(x) translated right h units and up k units will become ...
g(x) = f(x -h) +k
You want the function f(x) = x^2 to be translated right h=3 units, so it will become ...
g(x) = f(x -3) = (x -3)^2
g(x) = x^2 -6x +9