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djyliett [7]
3 years ago
13

. John has two coupons to use at a clothing store. One is for $20 off and the other is for 20% off. John wants to purchase a shi

rt with one of the coupons and wants to pay the least amount that he can. Choose the answer that BEST describes the situation. *
Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Complete question :

John has two coupons to use at a clothing store. One is for $20 off and the other is for 20% off. John wants to purchase a shirt with one of the coupons and wants to pay the least amount that he can. Choose the answer that BEST describes the situation. * 1 point A. The shirt will have the lowest price with the $20 off coupon. B. The shirt will have the lowest price with the 20% off coupon. C. The shirt will cost the same with either coupon. D. It depends on the cost of the shirt as to which coupon will help John pay the lowest price.

Answer: D. It depends on the cost of the shirt as to which coupon will help John pay the lowest price.

Step-by-step explanation:

Given two different coupon options :

First: 20% off

Second = $20 off

To our hase with one which enables one to pay the amount of money :

The price of the shirt will determine which of the coupons will give the least amount. For instance, a shirts which which cost below $100 will require the $20 off coupon in other to attain the least payment amount. However for shirts which cost above $100, the 20% coupon yield the least amount. Shirts which cost $100. Both coupons yields the same discount amount.

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Answer:

a = $80.3

b = $80

c = 4

d = 16

e = 4

f = 88

g = $132

h = 33%

i = 6

j = 30

k = 21

l = $90

m = $36

o = 21/50

p = 105

q = 7

r = 8 cm

s = 2.4

t = 4

u = 400cm

v = $280

Step-by-step Explanation:

==>Increasing $72 by 10% to get a

a = 110% of $72 = 110% × $73

a = 1.1 × 73

a = $80.3

==>a ($80.3) rounded to the nearest 10 to find b = $80

b = $80

==>Writing b (80) as the product of its primes I.e.

b = 2^{c} * 5

Thus, 80 = 2⁴ * 5

c = 4

==>Calculating c² = d

d = 4² = 16

d = 16

==> ²/8 of d = e

e = ²/8 × 16

e = 2 × 2

e = 4

==> e% of 2200 = f

f = 4% × 2200

f = 0.04 × 2200

f = 88

==>Converting £f to $ = g

If £1 = $1.5,

£88 = $g

1 × g = 1.5 × 88

g = $132

==> Converting \frac{g}{400} into % = h%

h = 132÷400 ×100

h = 0.33 × 100

h = 33%

==> √(h + 3) = i

i = √(33 + 3)

i = √36

i = 6

==> i × (3 + 2) = j

j = 6 × (3 + 2)

j = 6 × 5

j = 30

==> j% of 70 = k

k = j% × 70

k = 30% × 70

k = 0.3 × 70

k = 21

==> If k bottles = $63, 30 bottles = $l

21 bottles = $63

30 bottles = $l

21 × l = 63 × 30

21l = 1,890

l = 1,890/21

l = $90

==>If Tim and Mike (m) shares $90 in the ratio 3:2, Mike (m) would receive thus:

⅖ × $90 = m

m = 0.4 × 90

m = $36

==> √m + m = n

n = √36 + 36

n = 6 + 36

n = 42

==>Converting n% to fraction = o

Thus, o = 42/100

o = 21/50

==> o of 250 = p

p = 21/50 × 250

p = (21 × 250)/50

p = 21 × 5

p = 105

==> expressing p as a product of its primes i.e. p = 3 × 5 × q

105 = 3 × 5 × 7

Therefore, q = 7

==> Given a rectangle with dimensions of q cm and r cm, with an area of 56cm². Let's find r.

Area of rectangle = length × width = q × r

Area = 56 cm²

q = 7 cm

r = ?

56 = 7 × r

56/7 = r

8 = r

r = 8 cm

==> r × 0.3 = s

s = 8 × 0.3

s = 2.4

==> s ÷ 0.6 = t

t = 2.4 ÷ 0.6

t = 4

==> If t is in meters, converting t to cm will give us u

Since 1m = 100cm

4m = u cm

1 × u = 100 × 4

u = 400cm

==> Vikki (v) and John shares $u in the ratio 7:3. Thus, Vikki (v) would receive the following:

v = ⁷/10 × $400

v = 0.7 × 400

v = $280

8 0
3 years ago
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