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snow_tiger [21]
3 years ago
8

Pls help me or me fail

Mathematics
1 answer:
Mrac [35]3 years ago
5 0

Answer:

Cumin has the least price per ounce

Step-by-step explanation:

1. Divide each spice price to the size

Cumin -> 4.80/1.5= 3.2  

Ginger -> 3.60/ 0.8= 4.5  

Nutmeg -> 6.30/ 1.8= 3.5  

Thyme -> 4.50/ 1.25= 3.6  

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Marcy wants $205 in her bank account. If she has $85 now and adds $10 per week, how many weeks will it take her to reach her goa
DIA [1.3K]

Answer:

^^1 week and 5 days

Explanation:

If she has $85 now, and gains $10 per week, by the next week and 5 days, she should have her goal of $205. Hope it helps!

5 0
3 years ago
2/3 * (-3) h SD j ni djndjifnr​
Eddi Din [679]
2/3 x (-3)
-2/3 x3
= -2
5 0
3 years ago
If f(a) = K, then which of the following must be true? f(K) = a f -1(K) = a f -1(a) = K
Inessa05 [86]

Answer:


Step-by-step explanation:

given that f(a) = K

we have the options of

f(K) = a

f ⁻¹ (K) = a

f ⁻¹ (a) = K

Where f ⁻¹ denotes an inverse function.

If f(a) = K, then its reciprocate, f ⁻¹ (K) = a

because it is essentially undoing the original equation

6 0
3 years ago
A plane flew a total of 2220 miles its average speed was 555 mph how many hours did the plane fly
o-na [289]
2220 miles divided by 554mph would give you 4 hours
5 0
3 years ago
. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
3 years ago
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