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Naddika [18.5K]
3 years ago
14

Find the geometric mean between 7 and 12​

Mathematics
1 answer:
Fynjy0 [20]3 years ago
8 0

Answer:9.2

Step-by-step explanation:

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SOVA2 [1]

Answer:

Perpendicular means like making 4 right angles at the intersection, right? So do a light directly upwards through line t from point a. And for 2, do a line from point a to the center of BC, B to the center of AC, and C to the center of AB

Step-by-step explanation:

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2 years ago
riding find the length of the hypotenuse of the right triangle use pencil and paper explain how you can interpret the Pythagorea
noname [10]

Solution

Question 1:

- Use of the area of squares to explain the Pythagoras theorem is given below

- The 3 squares given above have dimensions: a, b, and c.

- The areas of the squares are given by:

\begin{gathered} \text{For square of length }a\to a^2 \\ \text{For square of length }b\to b^2 \\ \text{For square of length }c\to c^2 \end{gathered}

- The Pythagoras theorem states that:

"The sum of the areas of the smaller squares add up to the area of the biggest square"

Thus, we have:

c^2=a^2+b^2

Question 2:

- We can apply the theorem as follows:

\begin{gathered} 10^2+24^2=c^2 \\ 100+576=c^2 \\ 676=c^2 \\ \text{Take square root of both sides} \\  \\ c=\sqrt[]{676} \\ c=26 \end{gathered}

Thus, the value of c is 26

7 0
1 year ago
Help please!!!!!!! Math
noname [10]

Answer:

y=15

Step-by-step explanation:

u can find y int by making the value of x=0

so

0^2-5*0+15=y

y=15

8 0
3 years ago
tina wants to make flyers promoting a library book sale. the printer charges $40 plus $0.03 per flyer. how many flyers can tina
lukranit [14]
466 fylers for 53.98. that is the answer
4 0
4 years ago
Read 2 more answers
14. Let g represent Gupta's age. You can solve the equation 2g - 5+ g = 31 to find g. Which property would not be used in solvin
True [87]

Answer:

B. Commutative Property of Addition

Explanation:

To find out the property that would not be used in solving this equation, we solve for g.

\begin{gathered} 2g-5+g=31 \\ 3g-5=31 \\ \text{Add 5 to both sides} \\ 3g-5+5=31+5 \\ 3g=36 \\ \text{Divide both sides by 3} \\ \frac{3g}{3}=\frac{36}{3} \\ g=12 \end{gathered}

We have applied the following:

A. Addition Property of Equality/D. Subtraction Property of Equality​

C. Division Property of Equality

Therefore, the property that would not be used is:

B. Commutative Property of Addition

8 0
2 years ago
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