So basically
D=RT
distance=rate times time
D=233
carlos speed=55
maria speed=50
total time=4.4 hours
so therefor we have to represent
carlos time
maria time
carlos distance
maria dstance
let's say that
remember that whatever carlost drove is 233 minus maria (time and distance)
and since we are solving for maria time and distnace, solve in terms of them
maria time=t
maria distance=d
carlos time=4.4-t
carlos distance=233-d
remember total D=RT
find their seperate equations
carlos
233-d=55(4.4-t)
maria
d=50(t)
use them to solve
233-d=55(4.4-t)
subsitute 50(t) for d
233-50t=55(4.4-t)
add 50t to both sides
233=55(4.4-t)+50t
distribute using distributiver protperty (a(b+c)=ab+ac)
55(4.4-t)=242-55t
233=242-55t+50t
add like terms
233=242-5t
add 5t to both sides
233+5t=242
subtract 233 from both sides
5t=9
divdie both sides by 5
t=1.8
maria drove 1.8 hours
the answer is A
I believe the answer is C, x-3.
1. B
2. A
3. A
All of theses are true
Ok, so she has 14 tickets and each ride cost 2 so that can be modeled with the following expression: x= 14-2y since she initially bought 14 tickets and 2 times the number of tickets she spends. To find the equivalent expression you could basically switch up the formula like so: 7*2-2y=x because you just need an equivalent expression, and you don't need to have such a different formula or anything like that. Hope I helped!
