What is the distance between these points (-4,6) and (2,-3)
1 answer:
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Answer:
<u>1) 17.5×14×64</u>
- → 1568 in³
<u>2) volume= 0.5×3.6×10×5=</u>
- → 90
<u>3) d= 13, r=13/2= 6.5, h= 19</u>
- → v= πr²h
- → π(6.5)²×19
- → 2521.91 mm³
<u>4) Base Area= a+b/2×h</u>
- → (37+15)/2×25.7 cm²
- →26×25.7 cm²
- → 668.2 cm²
- height= 20cm
- voulme = 668.2×20
- → 13364 cm²
<u>5) L×W×H</u>
- → 25×7×18
- → 175×18
- → 3150 ft³
<u>6) v=πr²h</u>
- → π(3.2²)(8)
- → 81.92π
- → 257.36 km²
hope it helps...
have a great day!!
Answer:
Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
Step-by-step explanation:
Given the figure with dimensions. we have to find the area of given figure.
Area of figure=ar(1)+ar(2)+ar(3)
Area of region 1 = ar(ANGI)+ar(AIB)
Area of region 2 = ar(DHBC)
Area of region 3 = ar(GFEH)
Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha
=987.5 ha
Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.
Let the fencing be done through x m downward from B which divides the two into equal area.
⇒ Area of upper part above fencing=Area of lower part below fencing
⇒
Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.
