Question

The sum of three consecutive integers is 267. What is the largest integer?

Answer 1

Now, the integers are consecutive, one right after/before the next one.

so.. hmmm let's say our first one is "a".

if the first integer is "a", then the next one will be "a+1", one hop over.

and the last one will then be, another hop over, "(a+1)+1", or "a+2".

now, we know they add to 267, ok

$\bf a+(a+1)+(a+2)=267\implies a+a+1+a+2=267 \\\\\\ 3a=267-3\implies 3a=264\implies a=\cfrac{264}{3}\implies a=88$

and surely you'd know what the others are.

Answer 2

90+89=88= 267
x+x-1+x-2=267
3x-3=267
3x=270
x=90