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stepladder [879]
2 years ago
14

How do you solve parentheses 4×9+5) -10+16×6

Mathematics
1 answer:
Mamont248 [21]2 years ago
8 0

Answer:

(4×9+5) -10+16×6

36 + 5 - 10 + 16 * 6

41 - 10 + 96

41 + 86

127

Step-by-step explanation:

(4×9+5) -10+16×6

36 + 5 - 10 + 16 * 6

41 - 10 + 96

41 + 86

127

use PEMDAS

p = parantheses

e= exponent

m = multiply

d = divide

a = add

s = subtract

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Inessa05 [86]
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6 0
3 years ago
Make x the subject of the formula y= 2x +5
Kryger [21]

Answer:

x= (y-5)/2

Step-by-step explanation:

Isolate the x variable.

y= 2x +5

Subtract 5 from both sides.

y-5=2x

Divide both sides by 2.

(y-5)/2= x

5 0
2 years ago
Why is Point , Line , and Plane considered the 3 building blocks of geometry??? Please answer fast
tangare [24]
These 3 objects are used to make all of the other objects that we will use in geometry
3 0
3 years ago
Sally invests £8000 in a savings account. The account pays 2.8% compound interest per year work out the value of her investment
Alborosie

Answer: the value of her investment after 4 years is £8934.3

Step-by-step explanation:

The formula for determining compound interest is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount invested.

t represents the duration of the investment in years.

From the information given,

P = 8000

r = 2.8% = 2.8/100 = 0.028

n = 1 because it was compounded once in a year.

t = 4 years

Therefore,

A = 8000(1+0.028/1)^1 × 4

A = 8000(1+0.028)^4

A = 8000(1.028)^4

A = £8934.3 to the the nearest penny

6 0
3 years ago
Solve for x in the equation x2 - 4x-9 = 29.
erastova [34]

Answer:

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

Step-by-step explanation:

One is given the following equation;

x^2-4x-9=29

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

x^2-4x-9=29

x^2-4x-38=0

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

ax^2+bx+c

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Substitute the coefficients of the given equation in and solve for the roots;

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}

Simplify,

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}

Therefore, the following statement can be made;

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

8 0
2 years ago
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