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2 years ago

9 ft =_________in. How many inches????

Mathematics

1 answer:

lys-0071 [83]2 years ago

4 0

108 inches

hope this helped <3

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A car is traveling at the speed of 50 meters per second. What is the cars speed in kilometers per hour? How many kilometers will

Keith_Richards [23]

If the car is traveling at 50meters per second then you need to multiply 50 by 60 to get how many meters a minute then multiply that number by 60 to get meters per hour then take that number and divide it by 1000 to get kilometers per hour.

Answer:360 kilometers in 2 hours and the car is going 180 kilometers per hour

3 0

2 years ago

Consider f(x) = 4x^3 – 5, g(x) = 2x + 5 and h(x) =2x^2+2x. Which statement about (f + g – h) is true?

Natalka [10]

$\large{\mathcal{ANSWER:}}$

b) It is a cubic function of 4 terms.

In this case p(3) = t + 2 is synonymous for p = 3 + 2. Remember p is synonymous for y. So in this equation it is p = 5.

$\underline{\boxed{\purple{\tt{©⚘MissyRiel}}}}$

Hope this helps!

3 0

2 years ago

09:30 to 17:00 minus 30 minutes <br> How many hours is that ?

pentagon [3]

Answer:

7 hours

Step-by-step explanation:

9 : 30 to 17:00 = 7 hours 30 minutes

Minus 30 minutes = 7 hours

6 0

2 years ago

Please help!! Write in simplest radical form: √7/8 Show how you figured it out

12345 [234]

Given expression: $\sqrt{\frac{7}{8}}$ .

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$=\frac{\sqrt{7}}{\sqrt{8}}$

$\sqrt{8}=\sqrt{2^2\cdot \:2}=2\sqrt{2}$

$\frac{\sqrt{7}}{\sqrt{8}} =\frac{\sqrt{7}}{2\sqrt{2}}$

$\mathrm{Rationalize\:}\frac{\sqrt{7}}{2\sqrt{2}}$

$\mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{2}}{\sqrt{2}}$

$=\frac{\sqrt{7}\sqrt{2}}{2\sqrt{2}\sqrt{2}}$

$=\frac{\sqrt{14}}{4}$

$=\frac{\sqrt{14}}{4}$ .

3 0

3 years ago

If M is the midpoint of XY, find the coordinates of X if M(-3,-1) and Y(-8,6)

vova2212 [387]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
X&({{ a}}\quad ,&{{ b}})\quad 
% (c,d)
Y&({{ -8}}\quad ,&{{ 6}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)$

$\bf \left( \cfrac{-8+a}{2}~,~\cfrac{6+b}{2} \right)=\stackrel{M}{(-3,-1)}\implies 
\begin{cases}
\cfrac{-8+a}{2}=-3\\\\
-8+a=-6\\
\boxed{a=2}\\
----------\\
\cfrac{6+b}{2}=-1\\\\
6+b=-2\\
\boxed{b=-8}
\end{cases}$

5 0

2 years ago