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devlian [24]
3 years ago
5

Calculate the amount of money​ you'll have at the end of the indicated time​ period, assuming that you earn simple interest. You

deposit ​$3400 in an account with an annual interest of 4.5 ​% for 20years. The amount of money​ you'll have at the end of the years is
Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0

Answer:

The amount of money​ you'll have at the end of the years is 6460 dollars

Step-by-step explanation:

The total principal sum of money deposited = 3400 dollars

The annual rate of interest is 4.5 %

The time period for which the amount is invested = 20 years

As we know

A = P (1 + rt)

where A is the amount after 20 years

P is the principal sum of money

r is the rate of interest and

t is time period in years

Substituting the given values in above equation, we get -

A = 3400 (1 + \frac{4.5}{100} * 20)\\A = 6460dollars

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Help please! which choice represents the fraction below as a single exponential expression?
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Answer:

B

Step-by-step explanation:

use the exponent rule of division: you just subtract the exponents if the base is the same, so 4-8=-4

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Find the area of the kite
Leya [2.2K]

Answer:

144ft^2

Step-by-step explanation:

since it's a kite, there are two pairs of congruent (exactly the same shape) triangles

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\frac{6  \times 8}{2}=24

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so you would do 2(24+48)=144

6 0
2 years ago
The accompanying frequency distribution represents the square footage of a random sample of 500 houses that are owner occupied y
ioda

Answer:

\bar X = \frac{\sum x_i f_i}{n} = \frac{1220750}{500}=2441.5

s^2= \frac{3408029125 -\frac{(1220750)^2}{500}}{500-1} =856849.7

s= \sqrt{856849.7}=925.662

Step-by-step explanation:

For this case we can create the following table

Interval      Frequency (f)    Midpoint(xi)       xi *f      xi^2* f

0-499              9                       249.5            2245.5   560252.3

500-999         13                      749.5            9743.5    7302753

1000-1499      33                     1249.5          41233.5   51521258.25

1500-1999      115                    1749.5          201193.5  361986278.8

2000-2499     125                   2249.5         281187.5   632531281.3

2500-2999      81                    2749.5          222709.5 612339770.3

3000-3499      47                    3249.5         152726.5   496284761.8

3500-3999      45                    3749.5         168727.5    632643761.3

4000-4499      22                    4249.5         93489        397281505.5

4500-4999      10                     4749.5         47495        225577502.5

Total                500                                      1220750      3408029125

\sum f_i = 500 , \sum x_i f_i = 1220750, \sum x^2_i f_i = 3408029125

For this case we can calculate the sample mean with this formula:

\bar X = \frac{\sum x_i f_i}{n} = \frac{1220750}{500}=2441.5

And for the sample variance we can use the following formula:

s^2= \frac{\sum x^2_i f_i - \frac{(\sum x_i f_i)^2}{n}}{n-1}

And if we replace we got:

s^2= \frac{3408029125 -\frac{(1220750)^2}{500}}{500-1} =856849.7

And the deviation is just the square root of the sample variance and for this case is:

s= \sqrt{856849.7}=925.662

4 0
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Since there's only one choice with that slope, that is the choice you want.

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3 years ago
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