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devlian [24]
3 years ago
5

Calculate the amount of money​ you'll have at the end of the indicated time​ period, assuming that you earn simple interest. You

deposit ​$3400 in an account with an annual interest of 4.5 ​% for 20years. The amount of money​ you'll have at the end of the years is
Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0

Answer:

The amount of money​ you'll have at the end of the years is 6460 dollars

Step-by-step explanation:

The total principal sum of money deposited = 3400 dollars

The annual rate of interest is 4.5 %

The time period for which the amount is invested = 20 years

As we know

A = P (1 + rt)

where A is the amount after 20 years

P is the principal sum of money

r is the rate of interest and

t is time period in years

Substituting the given values in above equation, we get -

A = 3400 (1 + \frac{4.5}{100} * 20)\\A = 6460dollars

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alex41 [277]
You need k by itself, so the only way to do that is to divide both sides by 5
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The product of (1/2+3/4)(1/2-3/4)(i) and divided by (2-3i) is (multiplying complex numbers)
insens350 [35]
B) because i think its that answer
6 0
3 years ago
A lake polluted by bacteria is treated with an antibacterial chemical. Aftertdays, thenumber N of bacteria per milliliter of wat
jeyben [28]

Answer:

N(1)=50 is a minimum

N(15)=4391.7 is a maximum

Step-by-step explanation:

<u>Extrema values of functions </u>

If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.  

We are given a function (corrected)

N(t) = 20(t^2-lnt^2)+ 30

N(t) = 20(t^2-2lnt)+ 30

(a)

First, we take its derivative

N'(t) = 20(2t-\frac{2}{t})

Solve N'(t)=0

20(2t-\frac{2}{t})=0

Simplifying

2t^2-2=0

Solving for t

t=1\ ,t=-1

Only t=1 belongs to the valid interval 1\leqslant t\leqslant 15

Taking the second derivative

N''(t) = 20(2+\frac{2}{t^2})

Which is always positive, so t=1 is a minimum

(b)

N(1)=20(1^2-2ln1)+ 30

N(1)=50 is a minimum

(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15

(d)

N(15)=20(15^2-2ln15)+ 30

N(15)=4391.7 is a maximum

7 0
3 years ago
I NEED HELP ASAP PLEASE!!!!!
Bess [88]
A

plug in x = -1 to both sides and you get 1 as the answer for both sides.

8 0
3 years ago
Read 2 more answers
A gardener is planting two types of trees:
ICE Princess25 [194]

Answer:

After 1 year, both the tress will be of the same height.

Step-by-step explanation:

Let us assume in x years, both trees  have same height.

Type A  is 7 feet tall and grows at a rate of 8 inches per year.

⇒The growth of tree A in x years = x times  ( Height growth each year)

                                                        = 8 (x)  = 8 x

⇒Actual height of tree A in x years  = Initial Height + Growth in x years

                                                             = 7 + 8 x

or, the height of tree A after  x years  = 7 + 8x

Type B is 9 feet tall and grows at a rate of 6 inches per year.

⇒The growth of tree B in x years = x times  ( Height growth each year)

                                                        = 6 (x)  = 6 x

⇒Actual height of tree B in x years  = Initial Height + Growth in x years

                                                             = 9 + 6 x

or, the height of tree B after  x years  = 9 + 6x

According to the question:

After x years, Height of tree A  =Height of tree B

⇒7 + 8x   = 9 + 6x

or, 8x - 6x = 9 - 7

or, 2 x  = 2

or, x  =  2/2  = 1    ⇒ x  = 1

Hence, after 1 year, both the tress will be of the same height.

5 0
3 years ago
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