You need k by itself, so the only way to do that is to divide both sides by 5
B) because i think its that answer
Answer:
N(1)=50 is a minimum
N(15)=4391.7 is a maximum
Step-by-step explanation:
<u>Extrema values of functions
</u>
If the first and second derivative of a function f exists, then f'(a)=0 will produce values for a called critical points. If a is a critical point and f''(a) is negative, then x=a is a local maximum, if f''(a) is positive, then x=a is a local minimum.
We are given a function (corrected)


(a)
First, we take its derivative

Solve N'(t)=0

Simplifying

Solving for t

Only t=1 belongs to the valid interval 
Taking the second derivative

Which is always positive, so t=1 is a minimum
(b)

N(1)=50 is a minimum
(c) Since no local maximum can be found, we test for the endpoints. t=1 was already determined as a minimum, we take t=15
(d)

N(15)=4391.7 is a maximum
A
plug in x = -1 to both sides and you get 1 as the answer for both sides.
Answer:
After 1 year, both the tress will be of the same height.
Step-by-step explanation:
Let us assume in x years, both trees have same height.
Type A is 7 feet tall and grows at a rate of 8 inches per year.
⇒The growth of tree A in x years = x times ( Height growth each year)
= 8 (x) = 8 x
⇒Actual height of tree A in x years = Initial Height + Growth in x years
= 7 + 8 x
or, the height of tree A after x years = 7 + 8x
Type B is 9 feet tall and grows at a rate of 6 inches per year.
⇒The growth of tree B in x years = x times ( Height growth each year)
= 6 (x) = 6 x
⇒Actual height of tree B in x years = Initial Height + Growth in x years
= 9 + 6 x
or, the height of tree B after x years = 9 + 6x
According to the question:
After x years, Height of tree A =Height of tree B
⇒7 + 8x = 9 + 6x
or, 8x - 6x = 9 - 7
or, 2 x = 2
or, x = 2/2 = 1 ⇒ x = 1
Hence, after 1 year, both the tress will be of the same height.