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devlian [24]
3 years ago
5

Calculate the amount of money​ you'll have at the end of the indicated time​ period, assuming that you earn simple interest. You

deposit ​$3400 in an account with an annual interest of 4.5 ​% for 20years. The amount of money​ you'll have at the end of the years is
Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0

Answer:

The amount of money​ you'll have at the end of the years is 6460 dollars

Step-by-step explanation:

The total principal sum of money deposited = 3400 dollars

The annual rate of interest is 4.5 %

The time period for which the amount is invested = 20 years

As we know

A = P (1 + rt)

where A is the amount after 20 years

P is the principal sum of money

r is the rate of interest and

t is time period in years

Substituting the given values in above equation, we get -

A = 3400 (1 + \frac{4.5}{100} * 20)\\A = 6460dollars

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Unit rate is in the quantity of one.
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In the right triangle above a=2.7 and b=4.3. Find the value of c, rounded to the nearest tenth
morpeh [17]

Answer:

  5.1

Step-by-step explanation:

Since there is no diagram provided here, we assume that c is the length of the hypotenuse, so we have ...

  c² = a² +b² . . . . . . Pythagorean theorem

  c² = 2.7² +4.3² = 25.78

  c = √25.78 ≈ 5.0774

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7 0
3 years ago
Find an angle between 0° and 360° that is coterminal with the given angle
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Add or subtract 360 degrees to find a coterminous angle. Since the questions wants you to find one between 0-360, you should subtract 360.
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5 0
2 years ago
Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)
lisov135 [29]

Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

Step-by-step explanation:

(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

Multiply 2x-3y=3 by 2:

\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}

Subtract the equations

4x-6y=3\\-\\4x-6y=6\\------\\0=-3

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

Isolate x for 4x-6y=10

x=\frac{5+3y}{2}

Substitute x=\frac{5+3y}{2} into the second equation

16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40

The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

3 0
3 years ago
The lengths of the sides of a right triangle are a and b, and the hypotenuse is
mamaluj [8]
A^2+b^2=c^2
(2sqrt3)^2+b^2=16
12+b^2=16
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b=2
Now triangle area is A=1/2 bh
so
A=(1/2)(2)(2sqrt3)
A=2sqrt3
5 0
3 years ago
Read 2 more answers
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