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1 year ago

The constraints of a problem are listed below. What are the vertices of the feasible region?

1 answer:

6 0

We will draw the graph according to the given
constraints
NOTE: when we draw the graph from
constraints inequalities becomes equalities just
to draw the graph
Given constraints are:
Ar + 34 ≤ 12
20 + 64 <15
Now we draw the graph of given constraints
using graphing calculator. Please see the
attachment for the graph. Shaded region is the
feasible region

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WHAT IS 4 TIMES TWO THIRDS IN A MIXED FRACTION

Alex73 [517]

$\frac{4}{1}$ × $\frac{2}{3}$ = $\frac{8}{3}$
You then divide the numerator(top) by the denominator(bottom)
$\frac{8}{3}$ = $2 \frac{2}{3}$
Your answer is $2 \frac{2}{3}$

3 0

3 years ago

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The diagonal AC is drawn in parallelogram ABCD Which method can NOT be used to prove that AABC is congruent to ACDA?

diamong [38]

Answer:

B SSA

Step-by-step explanation:

Geometric proofs can be used to show that the two triangles are congruent using ASA, SAS and SSS.

However, there is no such thing as SSA in geometry because an angle and two sides can not show congruence of triangles. This is so because the angle is not an included angle.

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3 years ago

Answer ASAP!.......... I need help on 34 more questions.

lianna [129]

Step-by-step explanation:

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2 years ago

A+2/a-5÷a+1/a2-8a+15

krok68 [10]

For $A+\frac{2}{a}-\frac{5}{a}+\frac{1}{a^2}-8a+15$

Combine the fractions $\frac{2}{a} - \frac{5}{a} \ \textgreater \ \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \ \frac{2-5}{a}$

$\mathrm{Subtract\:the\:numbers:}\:2-5=-3 \ \textgreater \ \frac{-3}{a}$

$\mathrm{Apply\:the\:fraction\:rule}:\ \frac{-a}{b}=-\frac{a}{b} \ \textgreater \ -\frac{3}{a}$

Therefore our final answer is $A-\frac{3}{a}+\frac{1}{a^2}-8a+15$

Hope this helps!

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2 years ago

It costs £430 to rent a cottage for the weekend. Last year it cost £400. What percentage increase is this?

Serjik [45]

INCREMENT

430-400=30

PERCENTAGE

(30/400)*100

(30/40)*100

300/40=

7.5% is your final answer

I hope I could help

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2 years ago

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