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Zinaida [17]
3 years ago
14

Case bought a 10 week old pig that weighed 30 kg. At 18 weeks the pig weighed 80 kg. The equation (18 − 10)w + 30 = 80 can be us

ed to find the number of kg (x) the pig gained each week. How many kilograms did the pig gain each week?

Mathematics
2 answers:
PIT_PIT [208]3 years ago
8 0

Answer:

6.25 kg

Step-by-step explanation:

kramer3 years ago
7 0

Answer:25/4

Step-by-step explanation:

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Does anyone know the answer?
laila [671]

Answer:

a. θ = 30°

b. μ = √3 / 15 ≈ 0.115

Step-by-step explanation:

Draw a free body diagram for each scenario (see attached figure).  The body has four forces acting on it:

  • Weight pulling down
  • Normal force perpendicular to the incline
  • Applied force parallel up the incline
  • Friction force parallel to the incline

Remember that friction opposes the direction of motion.  So when the body is sliding up, friction points down the incline.  And when the body is sliding down, friction points up the incline.

Now apply Newton's second law to each scenario, first in the normal direction, then in the parallel direction.

For sliding up, sum of the forces normal to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces parallel to the incline:

∑F = ma

P₁ − f − mg sin θ = 0

P₁ − Nμ − mg sin θ = 0

Substituting the expression for normal force:

P₁ − mgμ cos θ − mg sin θ = 0

Now for sliding down, sum of the forces normal to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

And sum of the forces parallel to the incline:

∑F = ma

P₂ + f − mg sin θ = 0

P₂ + Nμ − mg sin θ = 0

Substituting the expression for normal force:

P₂ + mgμ cos θ − mg sin θ = 0

We know that P₁ = 6 kg.wt, P₂ = 4 kg.wt, and mg = 10 kg.wt.

So we have two equations and two unknowns (μ and θ):

P₁ − mgμ cos θ − mg sin θ = 0

P₂ + mgμ cos θ − mg sin θ = 0

Let's start by adding the equations together:

P₁ + P₂ − 2 mg sin θ = 0

P₁ + P₂ = 2 mg sin θ

sin θ = (P₁ + P₂) / (2 mg)

Plugging in the values:

sin θ = (6 + 4) / (2 × 10)

sin θ = 1/2

θ = 30°

Now we can plug this into either equation and find μ.

P₁ − mgμ cos θ − mg sin θ = 0

6 − (10 cos 30°) μ − 10 sin 30° = 0

6 − 5√3 μ − 5 = 0

1 = 5√3 μ

μ = √3 / 15

μ ≈ 0.115

6 0
3 years ago
What is 19.2× 10^8 minutes in hours?
algol [13]
The awnser is 1920,000,000 I hope I helped you the decimal skips eight spaces
6 0
3 years ago
Can I get some help on this please? This is part 1 I will post part 2 later.
Darya [45]

Answer:

-2/3 (fixed it)

Step-by-step explanation:

3 0
3 years ago
Find the area of △ABC with side lengths b = 6 and c = 17, and included angle A = 135∘. Round your answer to the nearest tenth
Cloud [144]

Answer:

<u>Area = 36.1 sq. units</u>

Step-by-step explanation:

We will use the "included angle area" formula for a triangle to solve this problem.

The formula is:

A=\frac{1}{2}abSinC

Where

a and b are the two sides given

C is the angle given BETWEEN the two sides

From the problem, we can write:

the two sides are 6 & 17, so that will be "a" and "b" of the formula

the included angle is 135, so that will be "C" of the formula

Substituting, we find the answer:

A=\frac{1}{2}abSinC\\A=\frac{1}{2}(6)(17)Sin(135)\\A=36.06

Rounded to 1 decimal place,

<u>Area = 36.1 sq. units</u>

4 0
3 years ago
Duo makes makes 65% of his dumping with vegetarian fillings
devlian [24]

um this is not a question its just a statment

8 0
3 years ago
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