Question

Help pls wit algebra 2

Answer 1

Answer:

C

Step-by-step explanation:

If $R_A=3R_B, T_A+T_B=12,$ then

$R_A=3R_B\\ \\T_A=12-T_B$

Substitute them into the equation $R_AT_A=360:$

$3R_B\cdot (12-T_B)=360\\ \\36R_B-3R_BT_B=360\\ \\12R_B-R_BT_B=120$

Given $R_BT_B=60,$ then

$12R_B-60=120\\ \\12R_B=120+60\\ \\12R_B=180\\ \\R_B=15\\ \\15\cdot T_B=60\Rightarrow T_B=\dfrac{60}{15}=4\\ \\T_A=12-T_B=12-4=8\\ \\R_A\cdot 8=360\Rightarrow R_A=\dfrac{360}{8}=45$

Hence,

$R_A-R_B+T_A-T_B=45-15+8-4=30+4=34$